SQL查询替换UNION ALL与加入或东西

Question

现在我有3个表

订单：

ID |日期|机器|规划

GoodPieces：

ID |日期|机器|件| |产品

BadPieces：

ID |日期|机器|件| |产品|组件

查询的输出是

日期|机器|计划| GoodPieces | BadPieces

的实际查询是类似的东西：

SELECT 
    data.Date AS Date, 
    data.Machine AS Machine, 
    SUM(CASE WHEN data.type = 'Planning' THEN data.value END) AS Planning, 
    SUM(CASE WHEN data.type = 'GoodPieces' THEN data.value END) AS GoodPieces, 
    SUM(CASE WHEN data.type = 'BadPieces' THEN data.value END) AS BadPieces 
FROM 
     (SELECT 
      'Planning' AS Type, 
      Date AS Date, 
      Machine AS Machine, 
      Planning AS Value 
     FROM Orders 
     UNION ALL 
     SELECT 
      'GoodPieces', 
      Date, 
      Machine, 
      Pieces AS Value 
     FROM GoodPieces 
     UNION ALL 
     SELECT 
      'BadPieces' 
      Date, 
      Machine, 
      Pieces AS Value 
     FROM BadPieces) AS data 
GROUP BY 
    Date, 
    Machine 

我的问题，如果是有没有办法让这个3个表

订单相同的输出：

ID |日期|机|规划

GoodPieces：

的OrderID |件| |产品

BadPieces：

的OrderID |件| |产品|组件

感谢，

Answer 1

当然，只是在表中LEFT JOIN，总结相应的列：

SELECT 
    O.Date, 
    O.Machine, 
    SUM(COALESCE(O.Planning, 0)) AS Planning, 
    SUM(COALESCE(G.Pieces, 0)) AS GoodPieces, 
    SUM(COALESCE(B.Pieces, 0)) AS BadPieces 
FROM 
    Orders O 
LEFT JOIN 
    (SELECT G.OrderID, 
    SUM(COALESCE(G.Pieces, 0)) AS GoodPieces 
    FROM GoodPieces G 
    GROUP BY G.OrderID) G ON G.OrderID = O.ID 
LEFT JOIN 
    (SELECT B.OrderID, 
    SUM(COALESCE(B.Pieces, 0)) AS BadPieces 
    FROM BadPieces B 
    GROUP BY B.OrderID) B ON B.OrderID = O.ID 
GROUP BY 
    O.Date, 
    O.Machine; 

演示：http://www.sqlfiddle.com/#!3/09a73/17

编辑：更新到处理点由下式给出@MikaelEriksson的评论。