从函数返回多个值

Question

我有这个函数调用它时返回三个值。

function GetCashierDetail ($UserID){ 
     $GetCashierID = "SELECT cashiers_CashierID,cashiers_Total,cashiers_Last_Total 
     FROM `cashiers` 
     WHERE `cashiers_CashierCloseDate` is null and `cashiers_Status`='0' 
     and `cashiers_Delete` = '0' and `cashiers_User` = '".$UserID."'"; 
     $objQueryCashierID = mysql_query($GetCashierID) or die ("Error Query [".$strSQL."]"); 
     $GetCashierIDResult = mysql_fetch_array($objQueryCashierID); 
     $BillsCashierID = $GetCashierIDResult['cashiers_CashierID']; 
     $CashierTotal=$GetCashierIDResult['cashiers_Total']; 
     $CashierLastTotal=$GetCashierIDResult['cashiers_Last_Total']; 
     $num=mysql_affected_rows(); 
     // Return Data 
     return $cashier_data = array('cashierId'=>$BillsCashierID , 
          'CashierTotal'=>$CashierTotal , 
          'CashierLastTotal'=>$CashierLastTotal);      

} 

现在，当调用这个函数GetCashierDetail (11)我需要在可变打印$cashier_data这样

$ID = $BillsCashierID 

使用它的其他方式。

我会尝试

class Bills { 
    // Get Cashier ID 
function GetCashierDetail ($ausers_ID){ 
     $GetCashierID = "SELECT cashiers_CashierID,cashiers_Total,cashiers_Last_Total 
     FROM `cashiers` 
     WHERE `cashiers_CashierCloseDate` is null and `cashiers_Status`='0' 
     and `cashiers_Delete` = '0' and `cashiers_User` = '".$UserID."'"; 
     $objQueryCashierID = mysql_query($GetCashierID) or die ("Error Query [".$strSQL."]"); 
     $GetCashierIDResult = mysql_fetch_array($objQueryCashierID); 
     $BillsCashierID = $GetCashierIDResult['cashiers_CashierID']; 
     $CashierTotal=$GetCashierIDResult['cashiers_Total']; 
     $CashierLastTotal=$GetCashierIDResult['cashiers_Last_Total']; 
     $num=mysql_affected_rows(); 
     // Return Data 
     return $cashier_data = array('cashierId'=>$BillsCashierID , 
          'CashierTotal'=>$CashierTotal , 
          'CashierLastTotal'=>$CashierLastTotal); 
} 

} 

$BillDraftSubmit = new Bills(); 
$data=$BillDraftSubmit->GetCashierDetail(71); 
$cashierId=$data["cashierId"]; 
$CashierTotal=$data["CashierTotal"]; 
$CashierLastTotal=$data["CashierLastTotal"]; 
echo "cashierId".$cashierId; 
echo "<br>CashierTotal".$CashierTotal; 
echo "<br>CashierLastTotal".$CashierLastTotal; 

，但我不能让导致

Answer 1

刚刚返回数组，没有必要将它分配给什么。即

return array('cashierId'=>$BillsCashierID , 
         'CashierTotal'=>$CashierTotal , 
         'CashierLastTotal'=>$CashierLastTotal); 

或做

$cashier_data = array('cashierId'=>$BillsCashierID , 
         'CashierTotal'=>$CashierTotal , 
         'CashierLastTotal'=>$CashierLastTotal); 
return $cashier_data; 

那么当你用$cd = GetCashierDetail(1);返回它，你可以访问$cd['CashierTotal']

Answer 2

$return = GetCashierDetail(11); 
$id = $return['cashierId']; 

RTM：http://php.net/manual/en/language.types.array.php

Answer 3

为什么不返回只是一个数组？

 function GetCashierDetail ($UserID){ 
    $GetCashierID = "SELECT cashiers_CashierID,cashiers_Total,cashiers_Last_Total 
    FROM `cashiers` 
    WHERE `cashiers_CashierCloseDate` is null and `cashiers_Status`='0' 
    and `cashiers_Delete` = '0' and `cashiers_User` = '".$UserID."'"; 
    $objQueryCashierID = mysql_query($GetCashierID) or die ("Error Query [".$strSQL."]"); 
    $GetCashierIDResult = mysql_fetch_array($objQueryCashierID); 
    $BillsCashierID = $GetCashierIDResult['cashiers_CashierID']; 
    $CashierTotal=$GetCashierIDResult['cashiers_Total']; 
    $CashierLastTotal=$GetCashierIDResult['cashiers_Last_Total']; 
    $num=mysql_affected_rows(); 
    // Return Data 
    return array('cashierId'=>$BillsCashierID , 
         'CashierTotal'=>$CashierTotal , 
         'CashierLastTotal'=>$CashierLastTotal);      

} 

$user = GetCashierDetail($id); 
$ID = $user['cashierId']; 
echo $ID; 

Answer 4

//$UserID - your user's id 
$result = GetCashierDetail ($UserID); 
//now just using as normal array, for example 
echo $result['cashierId']; 

Answer 5

如何：

$arr = GetCashierDetail (11); 
extract($arr); 
print $cashierId." ".$CashierTotal." ".$CashierLastTotal; 

Answer 6

如果我明白你的问题正确，要显示出纳ID的价值。

你能做到这样的..

$cashierData = GetCashierDetail(11); 

$ID = $cashierData['cashierId']; 

echo 'cashier ID is: ' . $ID; 

同样你也可以通过$cashierData['CashierTotal']得到CashierTotal等

Answer 7

我不知道我是否肠道你的权利......

list($id,,) = GetCashierDetail(11); 

echo $id;