PHP MySQL查询不返回预期的结果

Question

的全套，我有以下mysql_query我已经放在一个PHP变量：

$equalDimensions_query = 
"SELECT 'allEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight = $maxImageHeight 
UNION ALL 
SELECT 'widthEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight != $maxImageHeight 
UNION ALL 
SELECT 'heightEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth != $maxImageWidth AND imgHeight = $maxImageHeight"; 

我使用下面的PHP将这些结果放入一个单关联数组：

$equalDimensions_data = mysql_query($equalDimensions_query) or die('MySql Error' . mysql_error()); 

while ($row = mysql_fetch_assoc($equalDimensions_data)) { 
    $cnt[$row['COL1']] = $row['imgCount']; 
} 

它是假设返回一组三个阵列与值第一个是第一个，第二个是widthEqual，第三个是heightEqual（顺序无关紧要）。

唉由于某种原因它是不返回allEqual：

Array 
(
    [heightEqual] => 0 
    [widthEqual] => 0 
) 

当我使用print_r原文“三阵列”的形式显示检索到的数据，我得到的只有相同的结果阵列：

Array 
(
    [COL1] => heightEqual 
    [imgCount] => 0 
) 
Array 
(
    [COL1] => widthEqual 
    [imgCount] => 0 
) 

然而，如果我用print_r没有循环如下：

$equalDimensions_data = mysql_query($equalDimensions_query) or die('MySql Error' . mysql_error()); 
$equalDimensions_array = mysql_fetch_assoc($equalDimensions_data); 

print("<pre>"); 
print_r($equalDimensions_array); 
print("</pre>"); 

我回到了以前缺少allEqual阵列：

Array 
(
    [COL1] => allEqual 
    [imgCount] => 2 
) 

据我所知，因为没有在该while循环的最后一种情况，我只返回一个的结果;但为什么呢，在while循环的情况下，allEqual的结果似乎被跳过了？这是我的代码问题吗？我感谢您提供的任何帮助。对于这样一个长期的问题，我表示歉意。我想确保尽可能提供尽可能多的信息。

---

你可以在这里下载我的数据库模式：https://files.me.com/stefanmelnychenko/453l4z

Answer 1

这是你复制。您不会更改变量或任何内容，以便复制任何错误（如果有）。

我检查你的schemma和一切都很好，这是一个PHP脚本：

<?PHP 

// Make a MySQL Connection 
mysql_connect("localhost", "root", "") or die(mysql_error()); 

//select database 
mysql_select_db("new_arrivals_imgs") or die(mysql_error()); 


$imgId=1; 
$maxImageHeight=1; 
$maxImageWidth=1; 

$equalDimensions_query = 
"SELECT 'allEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight = $maxImageHeight 
UNION ALL 
SELECT 'widthEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth = $maxImageWidth AND imgHeight != $maxImageHeight 
UNION ALL 
SELECT 'heightEqual' AS COL1,COUNT(*) AS imgCount FROM (
    SELECT imgHeight, imgWidth, imgId AS primaryId FROM primary_images 
    UNION ALL 
    SELECT imgHeight, imgWidth, primaryId FROM secondary_images 
) AS union_table 
WHERE primaryId = $imgId AND imgWidth != $maxImageWidth AND imgHeight = $maxImageHeight"; 

$equalDimensions_data = mysql_query($equalDimensions_query) 
or die('MySql Error' . mysql_error()); 

while ($row = mysql_fetch_assoc($equalDimensions_data)) { 
    $cnt[$row['COL1']] = $row['imgCount']; 
} 

print_r($cnt); 

?> 

，这是结果：