当前尝试按日期进行分组,但忽略提示它的时间,因为我的dgv按时间对其进行了分组,但我环顾四周,正在努力适应工作。这是可以工作的原始代码,但是按日期/时间分组。VB.net GROUP By日期忽略时间
Dim sql2
Try
connect()
sql2 = "SELECT r_datetime, SUM(r_quantity) FROM [r_repair] WHERE r_location = 'CNV' AND r_line =('" & computer_line & "') AND r_datetime >= @startdata2 AND r_datetime < @enddata2 AND r_area = 'DPMO(T)' GROUP BY r_datetime"
Dim adapter2 As New SqlDataAdapter(sql2, con)
With adapter2.SelectCommand.Parameters
.Clear()
.Add("@startdata2", SqlDbType.DateTime).Value = monthly_from.Value
.Add("@enddata2", SqlDbType.DateTime).Value = monthly_to.Value.AddDays(1)
End With
Dim table_stencil As New DataTable()
table_stencil.Locale = System.Globalization.CultureInfo.InvariantCulture
adapter2.Fill(table_stencil)
Me.bs_m_t.DataSource = table_stencil
dgv_m_t.DataSource = bs_m_t
disconnect()
dgv_m_t.RowHeadersWidth = "28"
dgv_m_t.Columns(0).HeaderText = "Date:"
dgv_m_t.Columns(1).HeaderText = "Quantity:"
dgv_m_t.EnableHeadersVisualStyles = False
Catch ex As System.Exception
End Try
任何想法的?
干杯, 皮特
就像一个治疗 - 只是一个简单的一,我的数据是02/07/2017和04/07/2017 - 它很容易让它显示一个日期,没有数据给它的数量为0,所以在dgv它将展示01/07/2017,02/07/2017,03/07/2017 .....? –
首先,我[很高兴帮助](http://meta.stackoverflow.com/questions/291325/how-to-show-appreciation-to-a-user-on-stackoverflow/291327#291327) 。其次,你可能想看看[这个链接](https://stackoverflow.com/questions/38218157/get-all-day-of-month-then-mapping-data-to-specific-date/38219556#38219556 )。 –