查询找到所有字符出现在字符串

Question

我有柱雇员和employeename

ID Name 
1 Empee1 
2 Emp1 

我需要O/P为

Name 
E - 3 m - 1 p - 1 1 - 1 
E - 1 m - 1 1 - 1 

Answer 1

我不知道有一个“好”方式来做到这一点，但下面会给你你的结果：

SELECT 
    CASE WHEN [NAME] LIKE '%A%' THEN 'A - ' + CONVERT (VARCHAR, LEN([NAME]) - LEN(REPLACE ([NAME], 'A', ''))) 
    ELSE '' END, 
    CASE WHEN [NAME] LIKE '%B%' THEN ' B - ' + CONVERT (VARCHAR, LEN([NAME]) - LEN(REPLACE ([NAME], 'B', ''))) 
    ELSE '' END, 
    ... 
    ... 
    CASE WHEN [NAME] LIKE '%Z%' THEN ' Z - ' + CONVERT (VARCHAR, LEN([NAME]) - LEN(REPLACE ([NAME], 'Z', ''))) 
    ELSE '' END, 
    CASE WHEN [NAME] LIKE '%0%' THEN ' 0 - ' + CONVERT (VARCHAR, LEN([NAME]) - LEN(REPLACE ([NAME], '0', ''))) 
    ELSE '' END, 
    ... 
    ... 
    CASE WHEN [NAME] LIKE '%9%' THEN ' 9 - ' + CONVERT (VARCHAR, LEN([NAME]) - LEN(REPLACE ([NAME], '9', ''))) 
    ELSE '' END 
FORM [Your TABLE name];