PHP字长密度/计数，计算为一个字符串

Question

鉴于一文中，我怎么能指望字长的密度/计数，让我得到这样

• 1个字母的单词输出52/1 ％
• 2字母的单词：34/0.5％
• 3字母词67/2％

实测值这一点，但对于蟒

• counting the word length in a file
• Index by word length

Answer 1

你可以通过拆分文本变成文字，用启动或者explode()（作为一个非常/太简单的解决方案）或preg_split()（允许的东西，更强大一点）：

$text = "this is some kind of text with several words"; 
$words = explode(' ', $text); 

接着，迭代的话，使用strlen()获得每个人的长度;并把那些长到一个数组：

$results = array(); 
foreach ($words as $word) { 
    $length = strlen($word); 
    if (isset($results[$length])) { 
     $results[$length]++; 
    } 
    else { 
     $results[$length] = 1; 
    } 

} 

如果您正在使用UTF-8，请参阅mb_strlen()。

在这个循环结束，$results应该是这样的：

array 
    4 => int 5 
    2 => int 2 
    7 => int 1 
    5 => int 1 

的话，你就需要计算百分比的总数，可以发现两种：

• 通过增加foreach循环内的计数器，
• 或在循环完成后通过在$results上致电array_sum()。

而对于百分比计算，这是一个有点数学 - 我不会是有帮助的，有关^^

Answer 2

您可以用空格爆炸的文本，然后为每个最终的字，计算字母的数量。如果有标点符号或任何其他字词分隔符，则必须考虑到这一点。

$lettercount = array(); 
$text = "lorem ipsum dolor sit amet"; 
foreach (explode(' ', $text) as $word) 
{ 
    @$lettercount[strlen($word)]++; // @ for avoiding E_NOTICE on first addition 
} 

foreach ($lettercount as $numletters => $numwords) 
{ 
    echo "$numletters letters: $numwords<br />\n"; 
} 

PS：我还没有证明这一点，但应该工作

Answer 3

你可以通过左右使用的preg_replace删除标点聪明。

$txt = "Sean Hoare, who was first named News of the World journalist to make hacking allegations, found dead at Watford home. His death is not being treated as suspiciou"; 

$txt = str_replace(" ", " ", $txt); 
$txt = str_replace(".", "", $txt); 
$txt = str_replace(",", "", $txt); 

$a = explode(" ", $txt); 

$cnt = array(); 
foreach ($a as $b) 
{ 
    if (isset($cnt[strlen($b)])) 
    $cnt[strlen($b)] += 1; 
    else 
    $cnt[strlen($b)] = 1; 
} 

foreach ($cnt as $k => $v) 
{ 
    echo $k . " letter words: " . $v . " " . round(($v * 100)/count($a)) . "%\n"; 
} 

Answer 4

My simple way to limit the number of words characters in some string with php. 


function checkWord_len($string, $nr_limit) { 
$text_words = explode(" ", $string); 
$text_count = count($text_words); 
for ($i=0; $i < $text_count; $i++){ //Get the array words from text 
// echo $text_words[$i] ; " 
//Get the array words from text 
$cc = (strlen($text_words[$i])) ;//Get the lenght char of each words from array 
if($cc > $nr_limit) //Check the limit 
{ 
$d = "0" ; 
} 
} 
return $d ; //Return the value or null 
} 

$string_to_check = " heare is your text to check"; //Text to check 
$nr_string_limit = '5' ; //Value of limit len word 
$rez_fin = checkWord_len($string_to_check,$nr_string_limit) ; 

if($rez_fin =='0') 
{ 
echo "false"; 
//Execute the false code 
} 
elseif($rez_fin == null) 
{ 
echo "true"; 
//Execute the true code 
} 

?>