的关联数组的每个词的出现次数,让所述阵列是作为PHP:计数在字符串
{
element [0] = 'Mary',
element [1] = 'Mary had a little',
element [2] = 'a lamb',
element [3] = 'Mary mary mary',
.
.
element [n] = 'lady'
}
输出:
Mary : 5
a : 2
had : 1
little : 1
lady : 1
的关联数组的每个词的出现次数,让所述阵列是作为PHP:计数在字符串
{
element [0] = 'Mary',
element [1] = 'Mary had a little',
element [2] = 'a lamb',
element [3] = 'Mary mary mary',
.
.
element [n] = 'lady'
}
输出:
Mary : 5
a : 2
had : 1
little : 1
lady : 1
<?php
$array=array(
0 => 'Mary',
1 => 'Mary had a little',
2 => 'a lamb',
3 => 'Mary mary mary',
4 => 'lady'
);
$data=array();
foreach($array as $sentence)
{
//gatering words in an array by spliting the sentence on space.
$data= array_merge($data,explode(" ", $sentence));
}
//counting values present in array for case sensitive
$result=array_count_values($data);
print_r($result); //Result 1
//counting values present in array for case insensitive by changing each array element to lowercase
$result=array_count_values(array_map("strtolower", $data));
print_r($result); //Result 2
输出:
//result 1
Array
(
[Mary] => 3
[had] => 1
[a] => 2
[little] => 1
[lamb] => 1
[mary] => 2
[lady] => 1
)
//result 2
Array
(
[mary] => 5
[had] => 1
[a] => 2
[little] => 1
[lamb] => 1
[lady] => 1
)
尽管这段代码可以解决这个问题,但[包括解释](http://meta.stackexchange.com/questions/114762/explaining-entirely-code-based-answers)确实有助于提高您的帖子的质量。请记住,您将来会为读者回答问题,而这些人可能不知道您的代码建议的原因。也请尽量不要用解释性注释来挤占代码,这会降低代码和解释的可读性! – Rizier123
@Rizier加解释 –
你可能每个字存储到与一个正则表达式的数组,然后使用http://php.net/manual/en/function.array-count-values.php计数唯一身份......或者你可以迭代并在空间上爆炸。 – chris85
请显示您迄今尝试过的内容 –
$ result = mysqli_query($ connection,$ query4); $ json = mysqli_fetch_all($ result,MYSQLI_ASSOC); echo json_encode($ json); – Lubi