在sql中加入计数

Question

我对SQL很陌生，并且试图做一些事情而不是愚蠢的方式。为了给出一些背景，我正在比较运营商分支机构的规划和实际使用情况，并且需要统计两者的发生情况。我有一个with subquery as返回类似以下

PLANNED | REALIZED 
---------+---------- 
TRUCK | BI-TREM 
TRUCK | TRUCK 
TRUCK | TRUCK 
TRUCK | TRUCK 
TRUCK | TRUCK 
CARRETA | CARRETA 
CARRETA | CARRETA 
TRUCK | KOMBI 
TRUCK | BI-TREM 
CARRETA | KOMBI 
CARRETA | KOMBI 
TRUCK | TRUCK 
CARRETA | CARRETA 
CARRETA | BI-TREM 
CARRETA | CARRETA 
CARRETA | CARRETA 
TRUCK | BI-TREM 

，想返回类似以下

VEHICLE | TOTAL_PLANNED | TOTAL_REALIZED 
--------+---------------+--------------- 
CARRETA | 8    | 5 
TRUCK | 9    | 5 
BI-TREM | 0    | 4 
KOMBI | 0    | 3 

我已经试过以下

select PLANNED, 
     count(*) as TOTAL_PLANNED 
     null as REALIZED, 
     0 as TOTAL_REALIZED 
from subquery 
group by PLANNED 

union all 

select null as PLANNED, 
     0 as TOTAL_PLANNED, 
     REALIZED, 
     count(*) as TOTAL_REALIZED 
from subquery 
group by REALIZED 

返回

CARRETA 8 NULL 0 
TRUCK 9 NULL 0 
NULL 0 BI-TREM 4 
NULL 0 CARRETA 5 
NULL 0 TRUCK 5 
NULL 0 KOMBI 3 

我也尝试了使用子查询的所有可用连接，但没有成功。事实上，RIGHT JOIN的作品，但只是因为所有计划的车辆也在实现方面：如果有一些没有，我会在VEHICLE列有一个NULL。

感谢您的帮助，即使只是一个指向SQL命令的指针。

PS：这个查询必须同时在SQL Server和Oracle上工作，所以我在努力争取纯SQL。

Answer 1

尝试：

SELECT PLANNED_REALIZED AS VEHICLE, 
     SUM(TOTAL_PLANNED) AS TOTAL_PLANNED, 
     SUM(TOTAL_REALIZED) AS TOTAL_REALIZED 
FROM 
(select PLANNED AS PLANNED_REALIZED, 
     1 as TOTAL_PLANNED 
     0 as TOTAL_REALIZED 
from subquery 
union all 
select REALIZED as PLANNED_REALIZED, 
     0 as TOTAL_PLANNED, 
     1 as TOTAL_REALIZED 
from subquery 
) SQ 
GROUP BY PLANNED_REALIZED 

Answer 2

我认为这应该工作：

select T.VEHICLE, 
     (SELECT count(*) FROM Table AS T1 WHERE T1.PLANNED = T.VEHICLE) AS TOTAL_PLANNED 
     (SELECT count(*) FROM Table AS T2 WHERE T2.REALIZED = T.VEHICLE) AS TOTAL_REALIZED, 
from (SELECT DISTINCT PLANNED AS VEHICLE FROM Table 
     UNION SELECT DISTINCT REALIZED AS VEHICLE FROM Table) AS T