获取JSON数据，其中值最接近数字X

Question

我有一个用户输入的数字X.以及JSON格式的数据列表。

**114** 80 145  175  240  320 
**123** 85 155  190  260  345 
**132** 90 170  205  280  370 

我想将X与第一列中的最接近的数字匹配，然后在该行中返回以下值。

不知道我是否以最好的方式格式化了JSON。但这里是我到目前为止有：http://jsfiddle.net/wuSux/

Answer 1

尝试这样：

var data = [{"Body Weight":114," Untrained": 80," Novice": 145," Intermediate": 175," Advanced": 240," Elite": 320}, 
      {"Body Weight":123," Untrained": 85," Novice": 155," Intermediate": 190," Advanced": 260," Elite": 345}, 
      {"Body Weight":132," Untrained": 90," Novice": 170," Intermediate": 205," Advanced": 280," Elite": 370}]; 

var x = 140, 
    difference = 0, 
    bestIndex = 0, 
    bestDifference = Infinity, 
    i, cur, bodyWeight; 

for (i = 0; i < data.length; i++) { 
    cur = data[i]; 
    bodyWeight = cur["Body Weight"]; 
    difference = Math.abs(x - bodyWeight); 
    if (difference < bestDifference) { 
     bestDifference = difference; 
     bestIndex = i; 
    } 
} 

console.log(data[bestIndex]); 

DEMO：http://jsfiddle.net/wuSux/2/

变化x值找到最接近号码。

Answer 2

更改您的数据，所以最后Body Weight是320代替"320+"，则：

function getClosest(x) { 
    for (var i = data.length - 1; i > -1; i--) { 
     if (x > data[i]["Body Weight"]) break 
    } 
    if (i === data.length - 1) return data[i]; 
    if (i === -1) return data[0]; 

    return data[i + +(x > ((data[i]["Body Weight"] + data[i + 1]["Body Weight"])/2))]; 
} 

DEMO：http://jsfiddle.net/s8Xge/

---

或者如果你喜欢：

function getClosest(x) { 
    for (var i = data.length - 1; i > -1; i--) { 
     if (x > data[i]["Body Weight"]) break 
    } 
    return i === data.length - 1          ? data[i] : 
      i === -1             ? data[0] : 
      (data[i]["Body Weight"] + data[i + 1]["Body Weight"])/2 ? data[i + 1] : 
                     data[i]; 
}