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运行此代码pyuv产卵一个过程,捕获其输出和错误:为什么pyuv.pipe.start_read(...)在pyuv.process.spawn上导致Segementation错误?
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import pyuv
def on_read(pipe, data, error):
print('data: ' + str(data))
def on_exit(process, exit_status, term_signal):
print('Process Terminated - exit code: ' + str(exit_status))
def start():
stdin_pipe = pyuv.Pipe(pyuv.Loop.default_loop())
stdout_pipe = pyuv.Pipe(pyuv.Loop.default_loop())
stderr_pipe = pyuv.Pipe(pyuv.Loop.default_loop())
stdout_pipe.start_read(on_read)
stderr_pipe.start_read(on_read)
stdio = [pyuv.StdIO(stream=stdin_pipe, flags=pyuv.UV_CREATE_PIPE | pyuv.UV_READABLE_PIPE),
pyuv.StdIO(stream=stdout_pipe, flags=pyuv.UV_CREATE_PIPE | pyuv.UV_WRITABLE_PIPE),
pyuv.StdIO(stream=stderr_pipe, flags=pyuv.UV_CREATE_PIPE | pyuv.UV_WRITABLE_PIPE)]
process = pyuv.Process(pyuv.Loop.default_loop())
process.spawn(loop=pyuv.Loop.default_loop(),
args=['/usr/bin/wget', 'http://www.google.com'],
exit_callback=on_exit,
stdio=stdio)
pyuv.Loop.default_loop().run()
if __name__ == '__main__':
start()
产生一个Segmentation fault (core dumped)
谈到了“start_read()调用的管道实例的作品,但不给我是stdout和stderr。
我缺少什么?
这是不是正确的方式来捕获pyuv派生进程的标准输出和标准错误?