根据表格数据查找每个部门的第三最大工资

Question

我需要找出table中每个部门的员工的3rd maximum salary。如果不存在3rd maximum salary则显示2nd maximum salary。如果没有2nd maximum salary存在，那么找到highest salary。如何在sql-server中实现这个结果？

的table结构如下

create table employee1(empid int, empname varchar(10), deptid int, salary money) 

insert into employee1 
select 1,'a',1, 1000 
union 
select 1,'b',1, 1200 
union 
select 1,'c',1, 1500 
union 
select 1,'c',1, 15700 
union 
select 1,'d',2, 1000 
union 
select 1,'e',2, 1200 
union 
select 1,'g',3, 1500 

我试图获得最大的薪水为每个类别使用row_number功能的常见方式给出。

;with cte 
as 
( 
select ROW_NUMBER() over(partition by deptid order by salary) as id, * from employee1 
) 
select * from cte 

Answer 1

Select EmpID,empname,deptid,salary 
From (
Select * 
     ,RN = Row_Number() over (Partition By deptid Order By Salary) 
     ,Cnt = sum(1) over (Partition By deptid) 
From employee1 
    ) A 
Where RN = case when Cnt<3 then Cnt else 3 end 

返回

Answer 2

答案取决于您是否想要关系以及如何处理它们。如果你不需要任何联系，即使一个员工与另一个员工联系，它也会成为下一个最高薪水，那么诀窍就是使用row_number，就像你在薪水中下降时显示的那样，然后使用另一个row_number来反转它。如果你不想使用row_number第二次你可以用一些其他的技术做得一样好，但第1步是找到最高的第2步是扭转这种秩序

; WITH cteRankSalariesByDepartment AS (
    SELECT 
     * 
     ,RowNum = DENSE_RANK() OVER (PARTITION BY deptid ORDER BY salary DESC) 
    FROM 
     employee1 
) 

, cteReverseRankHighestSalaries AS (
    SELECT 
     * 
     ,RowNum2 = DENSE_RANK() OVER (PARTITION BY deptid ORDER BY RowNum DESC) 
    FROM 
     cteRankSalariesByDepartment 
    WHERE 
     RowNum <= 3 
) 

SELECT * 
FROM 
    cteReverseRankHighestSalaries 
WHERE 
    RowNum2 = 1 

根据您的意见更新DENSE_RANK()你可以只需使用它代替row_number()，您将获得您的关系。

Answer 3

你可以尝试查询象下面这样：

select * from 
(
select 
empid, 
empname , 
deptid , 
salary , 
ROW_NUMBER() over(partition by deptid order by id desc) as rev_id 
from 
( 
select 
ROW_NUMBER() over(partition by deptid order by salary) as id, 
empid, 
empname , 
deptid , 
salary 
from employee1 
) 
t where id<=3 
)t where rev_id=1 

working demo

Answer 4

你可以使用UNION

;with cte 
as 
( 
select ROW_NUMBER() over(partition by deptid order by salary) as id, * from employee1 
) 

--get the 3rd highest 
select 
    * 
from cte 
where id = 3 

union 

--get the highest/max 
select 
    c.* 
from cte c 
--this determines the highest which salary for each dept 
inner join 
    (select deptid, max(id) id 
    from cte 
    group by deptid) x on x.deptid = c.deptid and x.id = c.id 
--this limits it on depts that aren't in the list in the first part of the query 
where 
    c.deptid not in (select deptid from cte where id = 3) 

Answer 5

只要你查询的需求数与条件ROW_NUMBER如下：

;with cte 
as 
( 
select ROW_NUMBER() over(partition by deptid order by salary desc) as id, 
    Cnt = count(*) over(partition by deptid), * from employee1 
) 
select * from cte where (cnt >= 3 and id = 3) 
or (cnt < 3 and id = 1) 

Answer 6

要增加你的问题我加了两个员工，在第三位置同样的薪水。

为了得到这个，你需要第一个dense_rank部门的工资。后，您需要倒L的工资等级和获取位置1

尝试

DECLARE @employee1 TABLE 
     ( 
     empid INT, 
     empname VARCHAR(10), 
     deptid INT, 
     salary MONEY 
    ) 

    INSERT @employee1 Values 
    (1,'a',1, 1000 ) 
,(1,'b',1, 1200) 
,(2,'bb',1, 1200) 
,(1,'c',1, 1500) 
,(3,'ccc',1, 1500) 
,(1,'c',1, 15700) 
,(1,'d',2, 1000) 
,(1,'e',2, 1200) 
,(1,'g',3, 1500) 

    WITH cte_rank 
     AS (SELECT Dense_rank() 
         OVER ( 
         partition BY deptid 
         ORDER BY salary) SalaryRank, 
        * 
      FROM @employee1), 
     cte_final 
     AS (SELECT Dense_rank() 
         OVER ( 
         partition BY deptid 
         ORDER BY salaryrank DESC) SalaryRankReverse, 
        * 
      FROM cte_rank 
      WHERE salaryrank <= 3) 
    SELECT * 
    FROM cte_final 
    WHERE salaryrankreverse = 1 

结果

SalaryRankReverse SalaryRank   empid  empname deptid  salary 
-------------------- -------------------- ----------- ---------- ----------- --------------------- 
1     3     1   c   1   1500.00 
1     3     3   ccc  1   1500.00 
1     2     1   e   2   1200.00 
1     1     1   g   3   1500.00