我需要将8位IplImage转换为32位IplImage。使用来自全网的文档我试过以下的东西:如何将8位OpenCV IplImage *转换为32位IplImage *?
// general code
img2 = cvCreateImage(cvSize(img->width, img->height), 32, 3);
int height = img->height;
int width = img->width;
int channels = img->nChannels;
int step1 = img->widthStep;
int step2 = img2->widthStep;
int depth1 = img->depth;
int depth2 = img2->depth;
uchar *data1 = (uchar *)img->imageData;
uchar *data2 = (uchar *)img2->imageData;
for(h=0;h<height;h++) for(w=0;w<width;w++) for(c=0;c<channels;c++) {
// attempt code...
}
// attempt one
// result: white image, two red spots which appear in the original image too.
// this is the closest result, what's going wrong?!
// see: http://files.dazjorz.com/cache/conversion.png
((float*)data2+h*step2+w*channels+c)[0] = data1[h*step1+w*channels+c];
// attempt two
// when I change float to unsigned long in both previous examples, I get a black screen.
// attempt three
// result: seemingly random data to the top of the screen.
data2[h*step2+w*channels*3+c] = data1[h*step1+w*channels+c];
data2[h*step2+w*channels*3+c+1] = 0x00;
data2[h*step2+w*channels*3+c+2] = 0x00;
// and then some other things. Nothing did what I wanted. I couldn't get an output
// image which looked the same as the input image.
正如你所看到的,我并不真正知道自己在做什么。我很想知道,但如果我能够正确完成这项工作,我会更加喜欢它。 感谢您的帮助!
1有该网页上的一些有趣的信息,代码段,其解释我所已经尝试过了,结果是一样的,但是请看下面的链接,查看一直出错的例子: http://files.dazjorz.com/cache/conversion.png – sgielen 2008-12-27 15:45:19
哇,是的,那是一个好的,你是对的!所以这给出了以下线索:对于红点,R是1.0,GB是0.0,而对于白色,三者都是1.0。因此,在转换时,RGB值为d从0到255转换为0.0到1.0。将值更改为b/255可使图像变为黑色+红色。 – sgielen 2008-12-27 17:50:57