的Android SQLite的ORDER BY不起作用

我有一个表5K左右行：

CREATE TABLE "words" ("id" INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL , "name" TEXT NOT NULL , "def" TEXT NOT NULL, "rand" INTEGER)

其中我使用“更新字数设置兰特=随机定期更新（）”

在机器人，当我创建使用利用rawQuery（）的光标以下：

SELECT w.id, w.name, w.def, w.rand FROM words w ORDER BY w.rand ASC;

返回的游标不会以正确的顺序迭代。例如。它将以下列顺序兰特值输出列：

-1298882092 
-2138143484 
-1115732861 
118839193 
...

有谁知道怎么回事吗？不应该这样工作吗？如果我在SQLiteManager中运行完全相同的查询，它会以正确的顺序返回结果，所以这似乎是特定于android/cursor的。

UPDATE：

这里采用的是Android的代码，我已经尝试了多种方法：

尝试1：

Cursor cursor = db.rawQuery("SELECT w.id, w.name, w.def, w.rand FROM words w ORDER BY w.rand ASC", new String[]{});

尝试2：

Cursor cursor = db.query("words", new String[]{"id", "name", "def", "rand"}, 
      null, null, null, null, "rand ASC");

在这两种情况下，我重复如下：

while(cursor.moveToNext()) { 
    ... 
    Log.i("Test", cursor.getInt(3)); 
    ... 
}

来源

2011-01-30 ghempton

不是Android，但它似乎在这里工作：http://ideone.com/GEnG3 – 2011-01-30 20:22:18

是的，它也适用于sqlitemanager，所以我认为它是特定于android的。实际案例也有5k行和rand列上的索引。 – ghempton 2011-01-30 20:23:43

我解决了它，是一个简单的疏忽。 random（）函数返回的值可以大于java int数据类型。这是产生溢出。切换到getLong（），一切正常。游标始终正确迭代。

来源

2011-01-30 21:23:01 ghempton

我有一个问题，android游标，rawquery和group by。结果没有下令。

这是表：

public static final String I_ID = "iid"; 
public static final String I_QID = "qid"; 
public static final String I_STATUS = "status"; 
public static final String I_PDATE = "pub_date"; 
public static final String I_TYPE = "tipo"; 
public static final String I_TITLE = "titolo"; 
public static final String I_LINK = "link"; 
public static final String I_QR = "qrcode"; 
public static final String I_DESC = "descrizione"; 

private static final String C_ITEM_T = 
     "CREATE TABLE \""+T_ITEM+"\" ("+ 
     "\""+I_ID+"\" INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL,"+ 
     "\""+I_QID+"\" INTEGER NOT NULL REFERENCES "+T_QUERY+"("+Q_ID+") ,"+ 
     "\""+I_STATUS+"\" INTEGER NOT NULL,"+ 
     "\""+I_PDATE+"\" TEXT NOT NULL,"+ 
     "\""+I_TYPE+"\" TEXT NOT NULL,"+ 
     "\""+I_TITLE+"\" TEXT NOT NULL,"+ 
     "\""+I_LINK+"\" TEXT UNIQUE NOT NULL,"+ 
     "\""+I_QR+"\" TEXT UNIQUE NOT NULL,"+ 
     "\""+I_DESC+"\" TEXT"+ 
     ");"; 

public static final String A_ID = "aid"; 
public static final String A_IID = "iid"; 
public static final String A_SIZE = "grandezza"; 
public static final String A_DURATION = "durata"; 
public static final String A_CHANNELS = "canali"; 
public static final String A_RATE = "sampleRate"; 
public static final String A_TORRENT = "torrent"; 
public static final String A_DOWNLOAD = "download"; 
public static final String A_LICENSE_URL = "licenza_url"; 
public static final String A_TAGS = "tags"; 
public static final String A_CREATOR = "creatore"; 

private static final String C_ATTR_T = 
     "CREATE TABLE \""+T_ATTR+"\" ("+ 
     "\""+A_ID+"\" INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL,"+ 
     "\""+A_IID+"\" INTEGER NOT NULL REFERENCES "+T_ITEM+"("+I_ID+") ,"+ 
     "\""+A_SIZE+"\" LONG NOT NULL,"+ 
     "\""+A_DURATION+"\" LONG NOT NULL,"+ 
     "\""+A_CHANNELS+"\" TEXT NOT NULL,"+ 
     "\""+A_RATE+"\" TEXT NOT NULL,"+ 
     "\""+A_TORRENT+"\" TEXT NOT NULL,"+ 
     "\""+A_DOWNLOAD+"\" TEXT NOT NULL,"+ 
     "\""+A_LICENSE_URL+"\"TEXT,"+ 
     "\""+A_TAGS+"\" TEXT,"+ 
     "\""+A_CREATOR+"\" TEXT,"+ 
     "UNIQUE ("+A_ID+","+A_IID+")"+ 
     ");";

这是我的查询：

public static final String FILL_GRID = "SELECT * "+ 
     "FROM "+ Db.T_ITEM + " i " + 
     "LEFT OUTER JOIN "+Db.T_ATTR+" a ON (i."+Db.I_ID+"=a."+Db.A_IID+ ")"+ 
     " WHERE i."+Db.I_QID+" = ? AND i."+Db.I_STATUS+" <> "+Db.STATUS_DELETED + 
        " GROUP BY ? ";

在这里，我如何使用它：

Cursor c = db.rawQuery(FILL_GRID, new String[]{String.valueOf(qid), order});

在哪里我确信，QID是一个整数，并命令i.titolo ASC或DESC

只为我工作的解决方法是修改查询通过clausole在rawquery调用方法移动组：

public static final String FILL_GRID = "SELECT * "+ 
     "FROM "+ Db.T_ITEM + " i " + 
     "LEFT OUTER JOIN "+Db.T_ATTR+" a ON (i."+Db.I_ID+"=a."+Db.A_IID+ ")"+ 
     " WHERE i."+Db.I_QID+" = ? AND i."+Db.I_STATUS+" <> "+Db.STATUS_DELETED; 

Cursor c = db.rawQuery(FILL_GRID + " ORDER BY " + order, new String[]{String.valueOf(qid)});

来源

2012-06-15 12:45:18 jedi

的Android SQLite的ORDER BY不起作用

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