0
我正在为android制作应用程序。我需要向数据库中插入一定的值。Android插入不起作用
这是从DatabaseHelper(使用SQLite)的方法:
public long insertMyAnime(MyList myList) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put("name", myList.getName());
values.put("description", myList.getDescription());
values.put("episodes", myList.getEpisodes());
values.put("genre", myList.getGenre());
values.put("rating", myList.getRating());
values.put("episodesWatched", myList.getEpisodesWatched());
values.put("stateId", myList.getStateId());
long id = db.insert("myList", null, values);
db.close();
return id;
}
而这正是我要插入的部分:
public void addAnime_onClick(View v){
anime = domParser.getAnime(name);
MyList myList = new MyList();
myList.setName(anime.getName());
myList.setDescription(anime.getDescription());
myList.setEpisodes(anime.getEpisodes());
myList.setGenre(anime.getGenre());
myList.setEpisodesWatched(0);
myList.setStateId(4);
myList.setRating(0);
db.insertMyAnime(myList);
}
而这正是该表如下所示:
//CREATE TABLE MYANIME
String CREATE_TABLE_MYLIST = "CREATE TABLE myList (" +
"id INTEGER PRIMARY KEY AUTOINCREMENT," +
"name TEXT," +
"description TEXT," +
"episodes INTEGER," +
"genre TEXT," +
"rating INTEGER," +
"episodesWatched INTEGER," +
"stateId INTEGER)";
db.execSQL(CREATE_TABLE_MYLIST);
从我按下按钮插入时,应用程序崩溃。
你知道这个问题可能是什么吗?你会帮助我这么多...
那么“插入不起作用”对你来说意味着什么? – laalto
正如我所说的,应用程序崩溃,“插入”并不难,所以我不认为答案是遥遥领先的...... – Dominickus
如果发生崩溃,那就是堆栈跟踪。展示下。 –