让我们假设我有一个Web项目和几个可以部署它的环境。我希望Maven一次构建多个工件(例如,用于开发产品)。我有一个A-war模块和一个A-ear模块(包含A-war)。每件战争神器可能包含仅与其环境有关的信息。Maven ear插件多个工件内容
首先,我配置了战模块pom.xml文件:
<build>
<pluginManagement>
<plugins>
<plugin>
<artifactId>maven-war-plugin</artifactId>
<executions>
<execution>
<id>package-prod</id>
<phase>package</phase>
<configuration>
<classifier>prod</classifier>
<webappDirectory>${project.build.directory}/${project.build.finalName}-prod</webappDirectory>
<webResources>
<resource>
<directory>src/env/prod</directory>
</resource>
</webResources>
</configuration>
<goals>
<goal>war</goal>
</goals>
</execution>
<execution>
<id>package-dev</id>
<phase>package</phase>
<configuration>
<classifier>dev</classifier>
<webappDirectory>${project.build.directory}/${project.build.finalName}-dev</webappDirectory>
<webResources>
<resource>
<directory>src/env/dev</directory>
</resource>
</webResources>
</configuration>
<goals>
<goal>war</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</pluginManagement>
<finalName>A-war</finalName>
</build>
这工作得很好 - 2 * 战争 * s的目标文件夹中创建:A-战争督促和A-战争-dev的。
现在我想要构建耳朵神器这些战争中的每一个。
这里是pom.xml中的在A-耳的主要内容模块:
<dependencies>
<dependency>
<groupId>gr.id</groupId>
<artifactId>A-war</artifactId>
<version>0.0.1-SNAPSHOT</version>
<classifier>prod</classifier>
<scope>provided</scope>
<type>war</type>
</dependency>
<dependency>
<groupId>gr.id</groupId>
<artifactId>A-war</artifactId>
<classifier>dev</classifier>
<version>0.0.1-SNAPSHOT</version>
<scope>provided</scope>
<type>war</type>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-ear-plugin</artifactId>
<version>2.8</version>
<executions>
<execution>
<id>package-dev</id>
<phase>package</phase>
<configuration>
<classifier>dev</classifier>
<version>5</version>
<modules>
<webModule>
<groupId>gr.id</groupId>
<artifactId>A-war</artifactId>
<classifier>dev</classifier>
<contextRoot>/A-war</contextRoot>
<bundleFileName>/A-war.war</bundleFileName>
</webModule>
</modules>
</configuration>
<goals>
<goal>ear</goal>
</goals>
</execution>
<execution>
<id>package-prod</id>
<phase>package</phase>
<configuration>
<classifier>prod</classifier>
<version>5</version>
<modules>
<webModule>
<groupId>gr.id</groupId>
<artifactId>A-war</artifactId>
<classifier>prod</classifier>
<contextRoot>/A-war</contextRoot>
<bundleFileName>/A-war.war</bundleFileName>
</webModule>
</modules>
</configuration>
<goals>
<goal>ear</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
<finalName>A-ear</finalName>
</build>
它还建立2 耳** S:A-耳dev.ear和A-耳刺。耳。并且这些* 耳朵 *中的每一个都包含A-war.war神器。除了一个小细节之外,一切都会好的:这些** war文件是一样的。我的意思是A-ear-dev.ear包含A-war-dev.war(它被重新命名为A-war.war),但是A-ear-prod.ear包含相同的A-war-dev.war而不是它自己的A-战争prod.war。 此外,当我改变执行顺序(移动创建高于dev的产品)时,这两个包含A-war-prod.war。
,我可以从Maven的输出,开始建设耳朵时看到**的IT拷贝第一战成第一**耳的文件夹,但第二个它没有:
[INFO] --- maven-ear-plugin:2.8:ear (package-dev) @ A-ear
---
[INFO] Copying artifact [war:gr.id:A-war:dev:0.0.1-SNAPSHOT] to [/A-war.war]
[INFO] Including custom manifest ....
[INFO] Copy ear sources to ...
[INFO] Building jar: <location>\A-ear\target\A-ear-dev.ear
....
[INFO] --- maven-ear-plugin:2.8:ear (package-prod) @ A-ear ---
[INFO] Copy ear sources to ...
[INFO] Including custom manifest file ...
[INFO] Building jar: <location>\A-ear\target\A-ear-prod.ear
所以也许任何人有一个想法,如何每次强制maven副本war文件?