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我已可以执行下面的脚本在SQL我怎样才能显示SQL字符串值的参数
Select Year as ' years between ' + @StartYear + '-' + @EndYear + ' value '
from tblYears
where Year Between @StartYear and @EndYear
我已可以执行下面的脚本在SQL我怎样才能显示SQL字符串值的参数
Select Year as ' years between ' + @StartYear + '-' + @EndYear + ' value '
from tblYears
where Year Between @StartYear and @EndYear
你有你的as
切换左右。这个名字来自最后
Select 'years between ' + @StartYear + '-' + @EndYear + ' value ' AS Year
from tblYears
where Year Between @StartYear and @EndYear
现在@StartYear和@EndYear也有可能不是CHAR/VARCHAR/NCHAR/nvarchar的,所以你需要将它们转换。我将在这里假设你的年份是一个4位整数。如果不是,你需要调整它。
Select 'years between ' + convert(char(4), @StartYear) + '-' + convert(char(4), @EndYear) + ' value ' AS Year
from tblYears
where Year Between @StartYear and @EndYear
我相信你想要的是这样的,你在哪里插入选定的行的值到最终的输出?
SELECT CONVERT(CHAR(4), Year) + ' year is between '
+ CONVERT((CHAR(4),@StartYear) +'-'+ CONVERT((CHAR(4),@EndYear) + ' values.'
FROM tblYears
WHERE Year BETWEEN @StartYear AND @EndYear
否则,您甚至不需要FROM或WHERE,因为您将一遍又一遍地打印相同的东西。然后,我会建议:
SELECT ' years between ' + CONVERT((CHAR(4),@StartYear) + '-'
+ CONVERT((CHAR(4),@EndYear) + ' value'
我相信'有'是错字...它应该是'如何'。不是吗?你能执行并看到你得到什么错误? – 2012-03-08 15:21:30
应该是'[alias] ='或' AS [别名]'。不知道你在哪里得到你正在使用的'[别名] AS '语法。 –
2012-03-08 15:40:11