我想查询存储在我的MongoDB中的java.util.UUID,使用与存储的UUID所基于的字符串相对应的字节[]。MongoDB [Java]:如何以字节[]格式查询存储的UUID?
我见过Mongo Driver自动将UUID转换为字节并将其存储为BinData(子类型)。下面是我用来保存UUID代码:
UUID originalUUID= UUID.fromString("7ee973c0-54b5-11e4-aaed-0002a5d5c51b");
MongoClient mongoClient = new MongoClient("localhost" , 27017);
DB db = mongoClient.getDB("test");
DBCollection coll = db.getCollection("test");
BasicDBObject query = new BasicDBObject("_id", originalUUID);
coll.save(query);
我知道我们可以很容易地检索与UUID对象在BasicDBObject值这个文件,但是我想用一个byte []代替。毕竟,它在我的Mongo中必须是字节吗? 我知道Java在发送给Mongo之前搞乱了字节顺序,但是我一直无法使它工作。我的检索代码是在这里:
String stringOne = "7ee973c0-54b5-11e4-aaed-0002a5d5c51b";
// It's the same UUID String
BasicDBObject find = new BasicDBObject("_id", stringOne.getBytes());
DBCursor cursor = null;
cursor = coll.find(find);
while(cursor.hasNext()){
BasicDBObject dbObject = (BasicDBObject)cursor.next();
byte[] received = (byte[])dbObject.get("_id");
System.out.println(new String(received));
}
我也试过小端编码是这样的:
byte[] bytes = new byte[16];
ByteBuffer bb = ByteBuffer.wrap(bytes);
bb.order(ByteOrder.LITTLE_ENDIAN);
bb.putLong(originalUUID.getMostSignificantBits());
bb.putLong(originalUUID.getLeastSignificantBits());
BasicDBObject find = new BasicDBObject("_id", bb.array()); //Also tried flipping bb.
这一切都不奏效。有人可以通过解决方案提供一些见解吗?
谢谢!
你可以得到光标? – 2014-11-14 17:27:38
我不明白。获得“光标”是什么意思? – 2014-11-14 17:56:42