我做了两个随机数从0到3 a=0;
b=3;
A=round(a+(b-a)*rand(1,1000));
B=round(a+(b-a)*rand(1,1000));
然后我他们中的每两位补充。然后我将其转换为二进制文件。 SUM = A + B;
binarySum = dec2bin(SUM);
,因为我想算的转变,我写这样的代码: s = 1;
for i = 1:100
int main() {
int x = 3613;
std::cout << "x= " << x << std::endl;
std::string xBin = std::bitset<16>(x).to_string();
std::cout << xBin << std::endl;
unsigned long xDecimal = st