如何将两个SQL SELECT语句结合

我有两个SQL SELECT语句，说如何将两个SQL SELECT语句结合

SELECT TOP (150) FoodID, COUNT(*) AS NumberOfFood FROM FoodTable WHERE FoodID IS NOT NULL AND FoodDate >= '2015-10-01' GROUP BY FoodID ORDER BY NumberOfFood DESC

我也有另外一个SQL语句

SELECT FoodSellerID, Market1, SellerLastName, SellerFirstName, PrimaryAddress1, PrimaryAddress2, PrimaryCity, PrimaryState, PrimaryZip FROM SellerTable, MarketTable 
WHERE Market1= MarketTable.MarketID

几个音符指出，FoodID查找到SellerTable，市场1查找到MarketTable。我的问题是我怎样才能结合并返回表格，如

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2017-02-23 Manny Reddington

请格式化您的查询，现在完全无法读取。 – HoneyBadger

请仅标记相关的DBMS – JohnHC

您应该开始使用ANSI-92样式的连接......它们现在已经使用了超过25年。这意味着使用join关键字，而不是在where语句中使用equals谓词。 –

曼尼，你将无法加入这两个没有共同领域的两个查询。如果你有一个共同的领域，那么你可以建立每个临时表并加入第三个查询。它看起来像FoodTable中的'Food ID'（来自第一个查询）。如果存在于SellerTable上，那么您可以加入这两个（并且加入MarketTable以从该表中获取行）。

这将是这个样子：

create temp table food_nums_temp as 
    SELECT TOP (150) FoodID, COUNT(*) AS NumberOfFood 
    FROM FoodTable 
    WHERE FoodID IS NOT NULL 
    AND FoodDate >= '2015-10-01' 
    GROUP BY FoodID 
    ORDER BY NumberOfFood DESC 
    ; 

    Create temp table seller_temp as 
    SELECT FoodSellerID, FoodID, 
    Market1, 
    SellerLastName, 
    SellerFirstName, 
    PrimaryAddress1, 
    PrimaryAddress2, 
    PrimaryCity, 
    PrimaryState, 
    PrimaryZip 
    FROM SellerTable, MarketTable 
    WHERE Market1= MarketTable.MarketID 
    ; 

    select a.*, b.SellerLastName 
    , b.SellerFirstName, b.PrimaryAddress1, b.PrimaryAddress2 
    , b.PrimaryCity, b.PrimaryState, b.PrimaryZip 
    from food_nums_temp a 
    inner join seller_temp b on a.FoodID = b.FoodID

编辑：明知完全DB访问（创建临时表）是不允许的，允许使用“与”（又名公共表表达式或CTE），以现阶段的数据在我们所需的查询之前：

with 
    food_nums_temp as (
    SELECT TOP (150) FoodID, COUNT(*) AS NumberOfFood 
    FROM FoodTable 
    WHERE FoodID IS NOT NULL 
    AND FoodDate >= '2015-10-01' 
    GROUP BY FoodID 
    ORDER BY NumberOfFood DESC 
    ),  

    seller_temp as 
    SELECT FoodSellerID, FoodID, 
    Market1, 
    SellerLastName, 
    SellerFirstName, 
    PrimaryAddress1, 
    PrimaryAddress2, 
    PrimaryCity, 
    PrimaryState, 
    PrimaryZip 
    FROM SellerTable, MarketTable 
    WHERE Market1= MarketTable.MarketID 
    ) 

    select a.*, b.SellerLastName 
    , b.SellerFirstName, b.PrimaryAddress1, b.PrimaryAddress2 
    , b.PrimaryCity, b.PrimaryState, b.PrimaryZip 
    from food_nums_temp a 
    inner join seller_temp b on a.FoodID = b.FoodID

来源

2017-02-23 15:30:41 kltft

请注意，我没有访问完整的数据库，我只看到，我试图从三个不同的表中拉出数据.... –

曼尼，我编辑答案使用通用表表达式（CTE，完成使用关键字'WITH'）在查询之前将数据分级。请参阅上面的内容。 – kltft

感谢您的帮助，最终得到它的工作。 –

，试试这个

SELECT FoodSellerID, 
     Market1, 
     SellerLastName, 
     SellerFirstName, 
     PrimaryAddress1, 
     PrimaryAddress2, 
     PrimaryCity, 
     PrimaryState, 
     PrimaryZip 
FROM SellerTable ST 
INNER JOIN MarketTable MT 
    ON ST.Market1 = MT.MarketID 
inner join 
    (
    SELECT FoodID, COUNT(*) AS NumberOfFood 
    FROM FoodTable 
    WHERE FoodID IS NOT NULL 
    AND FoodDate >= '2015-10-01' 
    GROUP BY FoodID 
    ) a1 
    on a1.FoodID = ST.FoodID

来源

2017-02-23 15:24:07 JohnHC

感谢评论我最终得到它的工作。 –

尝试这样的：

SELECT TOP (150) a.FoodID, COUNT(*) AS a.NumberOfFood,b.SellerLastName, b.SellerFirstName, b.PrimaryAddress1, b.PrimaryAddress2, b.PrimaryCity, b.PrimaryState, b.PrimaryZipFROM FoodTable a inner join SellerTable b on a.FoodID = b.FoodSellerID WHERE a.Market1= b.MarketTable.MarketID IS NOT NULL AND FoodDate >= '2015-10-01' GROUP BY a.FoodID, b.SellerLastName, b.SellerFirstName, b.PrimaryAddress1, b.PrimaryAddress2, b.PrimaryCity, 
b.PrimaryState, b.PrimaryZip ORDER BY a.NumberOfFood DESC

注：可能是另一种解决方案。

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2017-02-23 15:30:23

如何将两个SQL SELECT语句结合

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