将两个select语句合并为一个

查询1：

select scheduleentry.scheduledate, 
    patientdemographics.accountnumber, 
    patientdemographics.firstname, 
    patientdemographics.middleinitial, 
    patientdemographics.lastname, 
    patientdemographics.address1, 
    patientdemographics.address2, 
    patientdemographics.city, 
    patientdemographics.state, 
    patientdemographics.zipcode, 
    patientdemographics.dateofbirth, 
    patientdemographics.sex, 
    patientdemographics.hometelephone, 
    patientinsuranceprofiles.insurance1name, 
    patientinsuranceprofiles.insurance1policynumber, 
    patientinsuranceprofiles.insurance1policygroupnumber, 
    patientinsuranceprofiles.insurance1guarantorfirstname as insuredfirstname, 
    patientinsuranceprofiles.insurance1guarantormiddleinitial as insuredmiddleinitial, 
    patientinsuranceprofiles.insurance1guarantorlastname as insuredlastname, 
    patientinsuranceprofiles.insurance1guarantoraddress1 as insuredaddress1, 
    patientinsuranceprofiles.insurance1guarantoraddress2 as insuredaddress2, 
    patientinsuranceprofiles.insurance1guarantorcity as insuredcity, 
    patientinsuranceprofiles.insurance1guarantorstate as insuredstate, 
    patientinsuranceprofiles.insurance1guarantorzipcode as insuredzip, 
    patientinsuranceprofiles.insurance1guarantordateofbirth as insureddob, 
    patientinsuranceprofiles.insurance1guarantorsex as insuredsex, 
    patientinsuranceprofiles.insurance1guarantortelephonenumber as insuredhomenumber, 
    insurances.eligibilitypayornumber 
from patientdemographics 
inner join patientinsuranceprofiles 
on patientdemographics.accountnumber = patientinsuranceprofiles.patientaccountnumber 
inner join scheduleentry 
on patientinsuranceprofiles.patientaccountnumber = scheduleentry.patientaccount 
inner join insurances 
on patientinsuranceprofiles.insurance1mnemonic = insurances.mnemonic 
where datediff(d, getdate(), scheduledate) = 1 
    and patientinsuranceprofiles.activeflag = 1 
order by scheduledate asc

问题2：

select scheduleentry.scheduledate, 
    patientdemographics.accountnumber, 
    patientdemographics.firstname, 
    patientdemographics.middleinitial, 
    patientdemographics.lastname, 
    patientdemographics.address1, 
    patientdemographics.address2, 
    patientdemographics.city, 
    patientdemographics.state, 
    patientdemographics.zipcode, 
    patientdemographics.dateofbirth, 
    patientdemographics.sex, 
    patientdemographics.hometelephone, 
    patientinsuranceprofiles.insurance2name, 
    patientinsuranceprofiles.insurance2policynumber, 
    patientinsuranceprofiles.insurance2policygroupnumber, 
    patientinsuranceprofiles.insurance2guarantorfirstname as insuredfirstname, 
    patientinsuranceprofiles.insurance2guarantormiddleinitial as insuredmiddleinitial, 
    patientinsuranceprofiles.insurance2guarantorlastname as insuredlastname, 
    patientinsuranceprofiles.insurance2guarantoraddress1 as insuredaddress1, 
    patientinsuranceprofiles.insurance2guarantoraddress2 as insuredaddress2, 
    patientinsuranceprofiles.insurance2guarantorcity as insuredcity, 
    patientinsuranceprofiles.insurance2guarantorstate as insuredstate, 
    patientinsuranceprofiles.insurance2guarantorzipcode as insuredzip, 
    patientinsuranceprofiles.insurance2guarantordateofbirth as insureddob, 
    patientinsuranceprofiles.insurance2guarantorsex as insuredsex, 
    patientinsuranceprofiles.insurance2guarantortelephonenumber as insuredhomenumber, 
    insurances.eligibilitypayornumber 
from patientdemographics 
inner join patientinsuranceprofiles 
on patientdemographics.accountnumber = patientinsuranceprofiles.patientaccountnumber 
inner join scheduleentry 
on patientinsuranceprofiles.patientaccountnumber = scheduleentry.patientaccount 
inner join insurances 
on patientinsuranceprofiles.insurance2mnemonic = insurances.mnemonic 
where datediff(d, getdate(), scheduledate) = 1 
    and patientinsuranceprofiles.activeflag = 1 
order by scheduledate asc

来源

2017-10-10 John Molina

'union all'或许？ – Arvo

一种方法是使用UNION ALL方法，如其他人所建议的。

(Query 1) 
union all 
(Query 2)

对于您的情况，可能情况下，并且对连接条件的一点修改都可以使用。请尝试以下：

select se.scheduledate, 
    pd.accountnumber, 
    pd.firstname, 
    pd.middleinitial, 
    pd.lastname, 
    pd.address1, 
    pd.address2, 
    pd.city, 
    pd.state, 
    pd.zipcode, 
    pd.dateofbirth, 
    pd.sex, 
    pd.hometelephone, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1name      else pip.insurance2name end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1policynumber    else pip.insurance2policynumber end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1policygroupnumber  else pip.insurance2policygroupnumber end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantorfirstname  else pip.insurance2guarantorfirstname as insuredfirstname end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantormiddleinitial else pip.insurance2guarantormiddleinitial as insuredmiddleinitial end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantorlastname  else pip.insurance2guarantorlastname as insuredlastname end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantoraddress1  else pip.insurance2guarantoraddress1 as insuredaddress1 end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantoraddress2  else pip.insurance2guarantoraddress2 as insuredaddress2 end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantorcity   else pip.insurance2guarantorcity as insuredcity end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantorstate   else pip.insurance2guarantorstate as insuredstate end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantorzipcode   else pip.insurance2guarantorzipcode as insuredzip end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantordateofbirth  else pip.insurance2guarantordateofbirth as insureddob end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantorsex    else pip.insurance2guarantorsex as insuredsex end, 
    case when i.mnemonic = pip.insurance1mnemonic then pip.insurance1guarantortelephonenumber else pip.insurance2guarantortelephonenumber as insuredhomenumber end, 
    i.eligibilitypayornumber 
from patientdemographics pd 
inner join patientinsuranceprofiles pip 
on pd.accountnumber = pip.patientaccountnumber 
inner join scheduleentry se 
on pip.patientaccountnumber = se.patientaccount 
inner join insurances i 
on i.mnemonic in (pip.insurance1mnemonic, pip.insurance2mnemonic) 
where datediff(d, getdate(), scheduledate) = 1 
    and pip.activeflag = 1 
order by scheduledate asc

来源

2017-10-10 11:31:02 GurV

#GurV试过了。在Union –

附近获得不正确的语法@JohnMolina按照您首先运行的查询进行排序。 – Leonidas199x

你可以在两个查询之间使用UNION ALL例如

SELECT ... 
FROM ... 
WHERE... 

UNION ALL 

SELECT ... 
FROM .... 
WHERE...

你可以阅读有关UNION这里的区别UNION ALL：What is the difference between UNION and UNION ALL?

你也可以使用CTE - 如果有一列可以联接，例如

;WITH Query1 AS 
(
SELECT Column1 
FROM ... 
) 
,Query2 AS 
( 
SELECT Column1 
FROM ... 
) 
SELECT  * 
FROM  Query1 AS Q1 
INNER JOIN Query2 AS Q2 ON Q1.Column1 = Q2.Column1

来源

2017-10-10 11:24:10 Leonidas199x

将两个select语句合并为一个

回答

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