我有3个表格:项目,技能和project_skills。在项目表中,我持有项目的一般数据。第二个表技能我拥有技能ID和技能名称我也有project_skills表是持有项目的技能关系。下面是表的方案:如何创建这个复杂的查询?
CREATE TABLE IF NOT EXISTS `project_skills` (
`project_id` int(11) NOT NULL,
`skill_id` int(11) NOT NULL,
KEY `project_id` (`project_id`),
KEY `skill_id` (`skill_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci;
CREATE TABLE IF NOT EXISTS `projects` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`employer_id` int(11) NOT NULL,
`project_title` varchar(100) COLLATE utf8_turkish_ci NOT NULL,
`project_description` text COLLATE utf8_turkish_ci NOT NULL,
`project_budget` int(11) NOT NULL,
`project_allowedtime` int(11) NOT NULL,
`project_deadline` datetime NOT NULL,
`total_bids` int(11) NOT NULL,
`average_bid` int(11) NOT NULL,
`created` datetime NOT NULL,
`active` tinyint(1) NOT NULL,
PRIMARY KEY (`id`),
KEY `created` (`created`),
KEY `employer_id` (`employer_id`),
KEY `active` (`active`),
FULLTEXT KEY `project_title` (`project_title`,`project_description`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci AUTO_INCREMENT=3 ;
CREATE TABLE IF NOT EXISTS `skills` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`category` int(11) NOT NULL,
`name` varchar(100) COLLATE utf8_turkish_ci NOT NULL,
`seo_name` varchar(100) COLLATE utf8_turkish_ci NOT NULL,
`total_projects` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `seo_name` (`seo_name`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci AUTO_INCREMENT=224 ;
我要选择具有相关技能的名字项目。我想我必须使用JOIN,但我不知道该怎么办。由于
这是值得一读一个SQL教程作为复习。 http://www.w3schools.com/sql/sql_join.asp – 2010-06-05 14:45:56
请举例说明“相关技能名称”。 – 2010-06-05 20:47:30
技能ID - 项目ID关系在项目技能名称中保留,但我想要在技能表中保存的技能名称。我的意思是这些技能名称通过说“相关技能名称” – mTuran 2010-06-06 22:46:03