TSQL - SQL 2000

Question

我很苦恼这个。我有一个看起来像这样的表答：

 
Employee_ID  Dependant_FirstName  DOB 
1    John     12/12/1980 
1    Lisa     11/11/1982 
2    Mark     06/06/1985 
2    Shane     07/07/1982 
2    Mike     03/04/1990 
3    NULL     NULL 

，并希望这些数据表B这样的复制（明知有可能只在表A最多6名家属）：

 
Employee_IDDependant1_FirstNameDOB  Dependant2_FirstNameDOB   Dependant3_FirstNameDOB 
1   John     12/12/1980 Lisa     11/11/1982 NULL     NULL 
2   Mark     06/06/1985 Shane    07/07/1982 Mike     03/04/1990 
3   NULL     NULL  NULL     NULL  NULL     NULL 

非常感谢您的帮助。

马克

Answer 1

有一个看看这个例子：

http://ryanfarley.com/blog/archive/2005/02/17/1712.aspx

在这里，他是concatentating父键的子元素为一个字符串，它应该让你写出来的平纪录。

Answer 2

你可以

• 创建一个视图
• 计算一个fictuous排名
• 组查找每个最高排名EMPLOYEE_ID
• 返回结果。

注：我在例子

声明忽略，则DOB列

CREATE VIEW dbo.VIEW_Employees_Ranking AS 
    SELECT Ranking = ISNULL(e6.Employee_ID, 0) 
      + ISNULL(e5.Employee_ID, 0) 
      + ISNULL(e4.Employee_ID, 0) 
      + ISNULL(e3.Employee_ID, 0) 
      + ISNULL(e2.Employee_ID, 0) 
      + ISNULL(e1.Employee_ID, 0)   
      , e1.Employee_ID 
      , Name1 = e1.Dependant_FirstName 
      , Name2 = e2.Dependant_FirstName 
      , Name3 = e3.Dependant_FirstName 
      , Name4 = e4.Dependant_FirstName 
      , Name5 = e5.Dependant_FirstName 
      , Name6 = e6.Dependant_FirstName 
    FROM dbo.Employees e1 
      LEFT OUTER JOIN dbo.Employees e2 ON e2.Employee_ID = e1.Employee_ID AND e2.DOB > e1.DOB 
      LEFT OUTER JOIN dbo.Employees e3 ON e3.Employee_ID = e2.Employee_ID AND e3.DOB > e2.DOB 
      LEFT OUTER JOIN dbo.Employees e4 ON e4.Employee_ID = e3.Employee_ID AND e4.DOB > e3.DOB 
      LEFT OUTER JOIN dbo.Employees e5 ON e5.Employee_ID = e4.Employee_ID AND e5.DOB > e4.DOB 
      LEFT OUTER JOIN dbo.Employees e6 ON e6.Employee_ID = e5.Employee_ID AND e6.DOB > e5.DOB 
GO 

SELECT er.* 
FROM dbo.VIEW_Employees_Ranking er 
     INNER JOIN (
      SELECT Ranking = MAX(Ranking) 
        , Employee_ID 
      FROM dbo.VIEW_Employees_Ranking 
      GROUP BY 
        Employee_ID 
     ) ermax ON ermax.Ranking = er.Ranking AND ermax.Employee_ID = er.Employee_ID 

Answer 3

这只是您的示例数据的工作示例，给怎样的想法我会做。我正在使用基于出生日期和姓名的伪装依赖计数器。请记住，如果一名员工拥有同名双胞胎，那么他们就会中断，但如果他们这样做了，那么他们应该得到所有终身数据 - 他们已经获得的数据混淆:)

另外，请考虑升级SQL Server。或者将这种旋转转移到您的报表工具而不是数据库。

CREATE TABLE #employees (employee_id INTEGER, Dependant_FirstName VARCHAR(20), DOB DATETIME) 

INSERT INTO #employees VALUES (1,    'John',     '12/12/1980') 
INSERT INTO #employees VALUES (1,    'Lisa',     '11/11/1982') 
INSERT INTO #employees VALUES (2,    'Shane',     '07/07/1982') 
INSERT INTO #employees VALUES (2,    'Mark',     '06/06/1985') 
INSERT INTO #employees VALUES (2,    'Mike',     '03/04/1990') 
INSERT INTO #employees VALUES (3,    NULL,     NULL) 

SELECT 
    employee_id, 
    MAX(CASE WHEN dep_count = 1 THEN Dependant_FirstName ELSE NULL END) 'Dependant1_FirstName', 
    MAX(CASE WHEN dep_count = 1 THEN DOB ELSE NULL END) 'Dependant1_DOB', 
    MAX(CASE WHEN dep_count = 2 THEN Dependant_FirstName ELSE NULL END) 'Dependant2_FirstName', 
    MAX(CASE WHEN dep_count = 2 THEN DOB ELSE NULL END) 'Dependant2_DOB', 
    MAX(CASE WHEN dep_count = 3 THEN Dependant_FirstName ELSE NULL END) 'Dependant3_FirstName', 
    MAX(CASE WHEN dep_count = 3 THEN DOB ELSE NULL END) 'Dependant3_DOB' 
FROM 
    (
     SELECT 
      employee_id, 
      Dependant_FirstName, 
      DOB, 
      (
       SELECT 
        COUNT(*) 
       FROM 
        #employees deps 
       WHERE 
        #employees.employee_id = deps.employee_id AND 
        CONVERT(VARCHAR, #employees.DOB, 126) + #employees.Dependant_FirstName <= 
         CONVERT(VARCHAR, deps.DOB, 126) + deps.Dependant_FirstName 
      ) 'dep_count' 
     FROM 
      #employees 
    ) add_dep_count_query 
GROUP BY 
    employee_id 

Answer 4

请检查此代码，它可能适用于您。

declare @Emp_Id int 
declare @Name int 
declare @DOB int 
declare @Count int 
set @Count=1 
DECLARE x_cursor CURSOR FOR 
SELECT distinct Employee_ID from tableA 
OPEN x_cursor 
FETCH NEXT FROM x_cursor 
INTO @Emp_Id 
WHILE @@FETCH_STATUS = 0 
BEGIN 


DECLARE second_cursor CURSOR FOR 
SELECT distinct Dependant_FirstName,DOB from tableA 
where Employee_ID=@Emp_Id 
OPEN second_cursor 
FETCH NEXT FROM second_cursor 
INTO @Name,@DOB 

WHILE @@FETCH_STATUS = 0 
BEGIN 


if(@Count=1) 
    begin 
     insert into tableB (Employee_ID , Dependant1_FirstName,DOB) 
     values(@Emp_Id,@Name,@DOB) 
     set @Count=@Count+1 
    end 
else 
    begin 
     exec('Update tableB set Dependant'+@count+'_FirstName='+@Name+' ,DOB'+@Count+'='+@DOB+' where Employee_ID='+@Emp_Id) 
     set @Count=@Count+1 
    end 

    FETCH NEXT FROM second_cursor 
    INTO @Name,@DOB 
END 
CLOSE second_cursor 
DEALLOCATE second_cursor 


set @Count=1 
    FETCH NEXT FROM x_cursor 
    INTO @Emp_Id 

END 
CLOSE x_cursor; 
DEALLOCATE x_cursor 
GO