如何在char * func（）中正确删除用新[]分配的char数组？

Question

此函数正在将文本文件读入字符缓冲区并将指针返回到此缓冲区。

char * textfile_to_char(wchar_t *filename) 
{ 
    WIN32_FIND_DATA data; 
    if (FindFirstFile(filename,&data)==INVALID_HANDLE_VALUE) 
    { 
     wchar_t message[256]; 
     wsprintf(message,L"File could not be found %lp",filename); 
     MessageBox(0,message,0,0); 
     return NULL; 
    } 
    else 
    { 
     HANDLE hFile=CreateFile(filename,GENERIC_READ,FILE_SHARE_READ|FILE_SHARE_WRITE,0,OPEN_EXISTING,FILE_ATTRIBUTE_NORMAL|FILE_ATTRIBUTE_READONLY,0); 
     if (hFile==INVALID_HANDLE_VALUE) 
     { 
      wchar_t message[256]; 
      wsprintf(message,L"Error opening file: %lp",filename); 
      MessageBox(0,message,0,0); 
      return NULL; 
     } 
     else 
     { 
      OVERLAPPED overlapped; 
      memset(&overlapped,0,sizeof(overlapped)); 
      char * buffer=new char[data.nFileSizeLow]; 
      ReadFileEx(hFile,buffer,data.nFileSizeLow,&overlapped,0); 
      CloseHandle(hFile); 
      buffer[data.nFileSizeLow]=0; 
      return buffer; 
     } 
    } 
} 

现在，这里是一个代码多个片而言我用这个函数从这段文字

wchar_t filename[512]; 
wsprintf(filename,L"%s.vtx",_shader_name); 
id_vertex_shader=glCreateShader(GL_VERTEX_SHADER); 
id_fragment_shader=glCreateShader(GL_FRAGMENT_SHADER); 
char *shader_source=textfile_to_char(filename); 
char *buffers[2]={shader_source,0}; 
glShaderSource(id_vertex_shader,1,buffers,0); 
delete[] shader_source; 
glCompileShader(id_vertex_shader); 

源OpenGL着色和删除[] shader_source其实挺让我困惑，因为）它不” t工作，b）删除shader_source也不起作用。让我怎么删除它感谢

Answer 1

你做一个异步读取，然后指望它立即读取，然后删除该文件处理

添加调用GetOverlappedResult的readFileEx和CloseHandle的：

ReadFileEx(hFile,buffer,data.nFileSizeLow,&overlapped,0); 
WORD bytesRead; 
if(!GetOverlappedResult(hFile, &overlapped, &bytesRead, TRUE);){ 
    //check error and such 

} 
CloseHandle(hFile); 
buffer[bytesRead]=0; 

或只是使用ReadFile的不重叠的结构：

WORD bytesRead; 
ReadFile(hFile,buffer,data.nFileSizeLow,&bytesRead,0); 
CloseHandle(hFile);