聚合函数或GROUP BY子句中嵌套查询复杂

Question

我这个例子，我需要得到基于优先级的工作/任务百分比的列表：

Priority Percentages 
----------------------- 
1   %25 
11   %10 

task_events表：

task_events_id time missing_info job_id task_index machine_id event_type user scheduling_class priority cpu_request memory_request disk_space_request different_machines_restriction 

job_id其任务可以在多行中，所以我创建了新的列task_events_id作为PK，用于嵌套选择以获取每个作业和任务的信号行。然后应用此结果来获得每项工作的优先级。我想出了这个查询。这里的主要概念是，我有11个优先级。优先考虑有很多工作。每个作业都被分配到一个优先级。

Select 
    tes.[priority], (tes.total_priority * 100/(select sum(tes.total_priority)from tes)) as [percentage] 
From 
    (select 
     [priority], count(*) as total_priority 
    from 
     task_events as t 
    inner join 
     (select 
       max(task_events_id) as maxid, 1 as total 
      from 
       task_events 
      group by 
       job_id, task_index) as te on t.task_events_id = te.maxid 
    group by 
     [priority]) as tes 
group by 
    tes.[priority] 

这最好的我想出了，但总的是越来越复杂，任何建议

与此查询我得到这个错误：

无效的对象名称TES“。

while it's put'tes.total_priority'on last group by。

Answer 1

如果每个优先级，你想要的整体总量的百分之它，然后使用窗口功能：

select [priority], count(*) as total_priority, 
     count(*) * 1.0/sum(count(*)) over() as ratio 
from task_events t 
group by [priority]; 

Answer 2

其实你的查询只需要在最后group by额外领域的工作......添加tes.total_priority有.. 它没有工作，虽然 - 代码中删除

-- Code removed 

，但你可以通过删除inner join考虑这个简单的查询，并使用distinct代替

Select 
    tes.[priority], (tes.total_priority * 100.0/sum(tes.total_priority)) as [percentage] 
From 
    (select 
     [priority], count(*) as total_priority 
    from 
     (select 
      distinct [priority], job_id, task_index 
     from task_events) as t 
     ) as tes 
group by 
    tes.[priority], tes.total_priority 

或更多使用的窗函数

select 
    [priority], count(*) as total_priority, 
    count(*) * 100.0/sum(count(*)) over() as ratio 
from (select distinct [priority], job_id, task_index 
     from task_events) as t 
group by [priority]; 

，最后一个简单的一个，如果job_id你所需要的计算和task_index可以从子查询中删除..然后子查询可以删除通过替换count(*)与count(distinct job_id) ..但结果可能会不同于以前的查询取决于数据和哪一个是正确的？依赖于真正想从这些数据来实现..它只是建议，但..

select 
    [priority], count(distinct job_id) as total_priority, 
    count(distinct job_id) * 100.0/sum(count(distinct job_id)) over() as ratio 
from task_events t 
group by [priority];