MySQL SELECT Query - 减去一个SUM（）值与其他两个SUM（）值的总和

Question

我有两个SELECT语句给出值“TotalSales”和“VendorPay_Com”。我希望能够从一个MySQL语句中的TotalSales中减去VendorPay_Com以获得值“Outstanding_Funds”，但我还没有找到一个可靠的方法来做到这一点。

这些是我的两个语句：

查询1：

SELECT SUM(Price) AS TotalSales 
FROM PROPERTY 
WHERE Status = 'Sold'; 

查询2：

SELECT SUM(AC.Amount) AS VendorPay_Comm 
FROM (
SELECT Amount FROM lawyer_pays_vendor 
UNION ALL 
SELECT CommissionEarned AS `Amount` FROM COMMISSION AS C WHERE C.`status` = 'Paid') AS AC 

在这个问题上的任何帮助，将不胜感激:)

Answer 1

如下你可以这样做：

select (select ...) - (select ...) 

在您的例子，简单地说：

select 

(
SELECT SUM(Price) AS TotalSales 
FROM PROPERTY 
WHERE Status = 'Sold' 
) 
- 
(
SELECT SUM(AC.Amount) AS VendorPay_Comm 
FROM (
SELECT Amount FROM lawyer_pays_vendor 
UNION ALL 
SELECT CommissionEarned AS `Amount` FROM COMMISSION AS C WHERE C.`status` = 'Paid') AS AC 
) AS Outstanding_Funds 

Answer 2

尝试

SELECT TotalSales-VendorPay_Comm AS Outstanding_Funds 
    FROM 
(SELECT SUM(Price) AS TotalSales 
    FROM PROPERTY 
    WHERE Status = 'Sold') t1, 
(SELECT SUM(Amount) AS VendorPay_Comm 
    FROM (SELECT Amount FROM lawyer_pays_vendor 
      UNION ALL 
     SELECT CommissionEarned AS Amount 
      FROM COMMISSION 
      WHERE Status = 'Paid') t0) t2 

这里是sqlfiddle