我在这里是全新的,所以我对这里的写作风格不是很熟悉,所以如果问题看起来不像应该那么抱歉。 我的问题是,我如何创建一个对象数组,但不是默认的构造函数? 如果我有这样的事情:如何在创建对象数组时避免默认的构造函数?
set<movie> a(3);
set<movie> b(2);
和构造: 对于电影
movie::movie()
{
this->naziv=0;
this->reditelj=0;
this->trajanje=0;
}
movie::movie(char *name, char *red, int len)
{
this->naziv=new char[strlen(name)+1];
strcpy(naziv,name);
this->reditelj=new char[strlen(red)+1];
strcpy(reditelj,red);
this->trajanje=len;
}
而对于集:
template<class t>
set<t>::set()
{
this->br=0;
this->niz=0;
}
set<t>::set(int b)
{
this->br=b;
this->niz=new t[br];
}
答案是伟大的,但当然,他们教给我们一些关于C++的基本知识,如何创建类,模板类,我的意思是,从一开始就编写程序,所以现在我们不使用那些大多数哟你提到。这个任务就是用这种方式编写代码,那我该怎么做呢? 这个任务是做一个类和一个模板类,模板类实际上是一个对象数组,所以我应该创建一个对象,这是一个对象数组和其他一些函数。
这里是我的全部代码:
Set.h
#pragma once
#include<iostream>
using namespace std;
template<class t>
class set
{
int br;
t* niz;
public:
set();
set(int b);
~set();
set(set& copy);
int vrati_br_elem()
{
return br;
}
bool pripada(t elem);
set operator*(set& drugi);
friend istream& operator>> <>(istream& ulaz,set<t> &s);
friend ostream& operator<< <>(ostream& izlaz,set<t> &s);
};
template<class t>
set<t>::set()
{
this->br=0;
this->niz=0;
}
template<class t>
set<t>::set(int b)
{
this->br=b;
this->niz=new t[br];
}
template<class t>
set<t>::~set()
{
if(this->niz!=0)
delete [] niz;
}
template<class t>
bool set<t>::pripada(t elem)
{
for(int i=0;i<this->br;i++)
if(this->niz[i]=elem)
return true;
return false;
}
template<class t>
set<t> set<t>::operator *(set<t> &drugi)
{
int broj=0;
set<t> pom((this->br>drugi.br)?this->br:drugi.br);
for(int i=0;i<this->br;i++)
for(int j=0;j<drugi.br;j++)
if(this->niz[i]==drugi.niz[j])
pom.niz[broj++]=this->niz[i];
pom.br=broj;
return pom;
}
template<class t>
istream& operator>>(istream& ulaz,set<t> &s)
{
for(int i=0;i<s.br;i++)
cin>>s.niz[i];
return ulaz;
}
template<class t>
ostream& operator<<(ostream& izlaz,set<t> &s)
{
for(int i=0;i<s.br;i++)
cout<<endl<<s.niz[i]<<endl;
return izlaz;
}
template<class t>
set<t>::set(set<t> ©)
{
this->br=copy.br;
this->niz=new t[br];
for(int i=0;i<this->br;i++)
this->niz[i]=copy.niz[i];
}
movie.h
#include<iostream>
using namespace std;
class movie
{
char* naziv;
char* reditelj;
int trajanje;
public:
movie();
~movie();
movie(movie& copy);
movie(char* name,char* red,int len);
movie& operator=(movie& film);
bool operator==(movie& film);
friend istream& operator>>(istream& ulaz,movie& film);
friend ostream& operator<<(ostream& izlaz,movie& film);
};
movie.cpp
#include"movie.h"
using namespace std;
movie::movie()
{
this->naziv=0;
this->reditelj=0;
this->trajanje=0;
}
movie::~movie()
{
if(naziv!=0&&reditelj!=0)
{
delete [] naziv;
delete [] reditelj;
}
}
movie::movie(movie ©)
{
this->naziv=new char[strlen(copy.naziv)+1];
strcpy(this->naziv,copy.naziv);
this->reditelj=new char[strlen(copy.reditelj)+1];
strcpy(this->reditelj,copy.reditelj);
this->trajanje=copy.trajanje;
}
movie& movie::operator =(movie &film)
{
if(this!=&film)
{
delete [] naziv;
delete [] reditelj;
this->naziv=new char[strlen(film.naziv)+1];
strcpy(this->naziv,film.naziv);
this->reditelj=new char[strlen(film.reditelj)+1];
strcpy(this->reditelj,film.reditelj);
this->trajanje=film.trajanje;
}
return *this;
}
bool movie::operator ==(movie &film)
{
if(!strcmp(this->naziv,film.naziv)&&!strcmp(this->reditelj,film.reditelj)&&this->trajanje==film.trajanje)
return true;
return false;
}
istream& operator>>(istream& ulaz,movie& film)
{
ulaz>>film.naziv>>film.reditelj>>film.trajanje;
return ulaz;
}
ostream& operator<<(ostream& izlaz,movie& film)
{
izlaz<<endl<<film.naziv<<endl<<film.reditelj<<endl<<film.trajanje<<endl;
return izlaz;
}
movie::movie(char *name, char *red, int len)
{
this->naziv=new char[strlen(name)+1];
strcpy(naziv,name);
this->reditelj=new char[strlen(red)+1];
strcpy(reditelj,red);
this->trajanje=len;
}
'std :: allocator',可能用'std :: uninitialized_copy'或'std :: uninitialized_fill'。 – 2012-01-04 22:43:03
另外,不要将你的班级命名为'set',否则你会迷惑每个人。 'std :: set'比你所做的更为人所知。另外,欢迎来到堆栈溢出。 – 2012-01-04 22:43:55
您是否尝试使构造函数为私有?顺便说一句。你的问题格式很好:-) – rekire 2012-01-04 22:44:26