选择最频繁的值与总和

Question

我想找到每个员工与大多数收入的产品并列销售的最频繁的产品。我写了一些例子，以便更清楚。

DECLARE @Products TABLE(ID INT, ProductName NVARCHAR(50), Price DECIMAL) 
DECLARE @Employees TABLE(ID INT, EmployeeName NVARCHAR(50)) 
DECLARE @Sales TABLE(ID INT, EmployeeID INT, ProductID INT, Quantity INT) 

INSERT INTO @Products VALUES 
(1, N'Product1', 300), 
(2, N'Product2', 500), 
(3, N'Product3', 700), 
(4, N'Product4', 800) 

INSERT INTO @Employees VALUES 
(1, N'Employee1'), 
(2, N'Employee2'), 
(3, N'Employee3') 

INSERT INTO @Sales VALUES 
(1,1,2,3), 
(2,1,3,4), 
(3,1,2,5), 
(4,2,2,7), 
(5,2,4,3), 
(6,3,2,3), 
(7,3,2,9), 
(8,3,4,8) 

连接表看起来喜欢这样的：

我写了一些选择

SELECT 
    e.EmployeeName 
    ,p.ProductName 
    ,SUM(s.Quantity) AS Quantity  
    ,p.ProductName 
    ,SUM(s.Quantity * p.Price) AS Price 
FROM @Products p 
    INNER JOIN @Sales s ON s.ProductID = p.ID 
    INNER JOIN @Employees e ON s.EmployeeID = e.ID 
GROUP BY e.EmployeeName, p.ProductName 
ORDER BY SUM(s.Quantity) DESC, SUM(s.Quantity * p.Price) 

返回这个结果，这是不正确的。您注意到价格没有订购

我想写这个格式的选择，单独为每个雇员订购产品名称和总量，产品名称和价格总和。

预期的输出应该

EmployeeName  ProductName Quantity ProductName  Price 
------------  ----------- -------- -----------  ------ 
Employee3   Product2  12   Product4   6400 
Employee1   Product2  8   Product2   4000  
Employee3   Product4  8   Product2   6000 
Employee2   Product2  7   Product2   3500 
Employee1   Product3  4   Product3   2800 
Employee2   Product4  3   Product4   2400 

Answer 1

您所查询的是开始。然后你可以使用窗口函数和条件汇总：

SELECT EmployeeName, 
     MAX(CASE WHEN seqnum_q = 1 THEN ProductName END) as productname_q, 
     MAX(CASE WHEN seqnum_q = 1 THEN Quantity END) as quantity_q, 
     MAX(CASE WHEN seqnum_pq = 1 THEN ProductName END) as productname_pq, 
     MAX(CASE WHEN seqnum_pq = 1 THEN Quantity END) as quantity_pq 
FROM (SELECT e.EmployeeName, p.ProductName, 
      SUM(s.Quantity) AS Quantity, SUM(s.Quantity * p.Price) AS Price, 
      ROW_NUMBER() OVER (PARTITION BY e.EmployeeName 
           ORDER BY SUM(s.Quantity) DESC 
           ) as seqnum_q, 
      ROW_NUMBER() OVER (PARTITION BY e.EmployeeName 
           ORDER BY SUM(s.Quantity * p.Price) DESC 
           ) as seqnum_pq 
     FROM @Products p INNER JOIN 
      @Sales s 
      ON s.ProductID = p.ID INNER JOIN 
      @Employees e 
      ON s.EmployeeID = e.ID 
     GROUP BY e.EmployeeName, p.ProductName 
    ) ep 
GROUP BY EmployeeName; 

Answer 2

更改您的订单通过为：

ORDER BY SUM(s.Quantity) DESC, SUM(s.Quantity * p.Price) Desc 

Answer 3

试试这个：

SELECT 
    e.EmployeeName 
    ,p.ProductName 
    ,SUM(s.Quantity) AS Quantity  
    ,p.ProductName 
    ,SUM(s.Quantity * p.Price) AS Price 
FROM @Sales s 
    INNER JOIN @Products p ON s.ProductID = p.ID 
    INNER JOIN @Employees e ON s.EmployeeID = e.ID 

GROUP BY e.EmployeeName, p.ProductName 
ORDER BY e.EmployeeName, SUM(s.Quantity) DESC, SUM(s.Quantity * p.Price),p.ProductName