2017-04-02 178 views
0

我对MySQL不太熟悉,我尝试创建一个MySQL过程,从表中选择两个字段,将它们分配给一个变量,然后使用这些变量的值更新另一个表中的另一个字段,到目前为止,这是代码我有,但是当我运行它,我得到这个错误:我在这个过程查询中做错了什么?

ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SET @amnt = (SELECT initial_payment FROM pH值WHERE PAYMENT_STATUS = 'unconf' at line 5

这是我的代码:

DELIMITER // 
CREATE PROCEDURE check_for_days() 
BEGIN 
    SET @i = (SELECT COUNT(*) FROM `ph` WHERE `payment_status` = 'unconfirmed' && TIMESTAMPDIFF(DAY, `date_paired`, NOW()) > 2) ; 

    label1:WHILE @i>0 
     SET @amnt = (SELECT `initial_payment` FROM `ph` WHERE `payment_status` = 'unconfirmed' && TIMESTAMPDIFF(DAY, `date_paired`, NOW()) > 2 LIMIT 1); 
     SET @id_to_cred = (SELECT `to_pay_id` FROM `ph` WHERE `payment_status` = 'unconfirmed' && TIMESTAMPDIFF(DAY, `date_paired`, NOW()) > 2 LIMIT 1); 
     UPDATE `gh` SET `remaining_to_get` = + @amnt WHERE `u_id` = @id_to_cred; 
     DELETE FROM `ph` WHERE `payment_status` = 'unconfirmed' && TIMESTAMPDIFF(DAY, `date_paired`, NOW()) > 2 LIMIT 1; 
     SET @i = @i - 1; 
    END WHILE label1; 
END 
DELIMITER ; 
+0

它的'设置@i:= ...' – GurV

+0

问* *另一个问题。提供样本数据,所需结果以及存储过程应该执行的操作的解释。 –

回答

2

为您语法错误:

label1:WHILE @i>0 
    SET @amnt 

哪里是DO

label1:WHILE @i>0 DO 
     SET @amnt` 
+0

非常感谢,这是我的解决方案。 – ChasingShadows

+0

你欢迎我的朋友 – Cherif

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