使用数学函数的值在cocos2d-x中渲染

我在linux上，使用cocos2d-x为Android。

我已经创建了一个计算圆圈值的函数。

 
     // Circle point updateCircle() 
    // x = number of iteration · SamplingPeriod |-|-|-| 
    // y = A · sine (2 · PI · number of iteration · SamplingPeriod/Period) 
    int iterations = this->getNumberOfIterations(); 
    CCPoint centerPoint = this->getCenter(); 
    float x = centerPoint.x + this->getAmplitude() * cos(2 * M_PI * iterations * this->getSamplingPeriod() * this->getFrequency()); 
    float y = centerPoint.y + this->getAmplitude() * sin(2 * M_PI * iterations * this->getSamplingPeriod() * this->getFrequency()); 

    _newPoint = ccp(x, y); 

     // Create Array Actions 
    CCArray *myActionsArray = new CCArray(3); 

    // Set action move 
    CCAction *actionMove1 = CCMoveTo::create(this->getSamplingPeriod(), newPoint);       // Move to next point 
     CCAction *actionMove2 = CCCallFuncN::create(this, callfuncN_selector(GameObject::updateCircle));  // call again this function 

     // Insert Objects 
    myActionsArray->insertObject(actionMove1, 0); 
    myActionsArray->insertObject(actionMove2, 1); 

    // Create Sequence 
    CCAction *action = CCSequence::create(myActionsArray); 

     // Set Tags 
    action->setTag(kActionMove); 

    // Run 
    this->runAction(action); 

    // Set new call to put new point in SamplingFrequency ms 
    iterations += 1; 
    static const int maxIterationCycle = 1/(this->getSamplingPeriod() * this->getFrequency()); 
    if (iterations >= maxIterationCycle) 
    { 
     iterations = 1; 
    } 

    this->setNumberOfIterations(iterations); 
    CCLog("texttx Iterations %d/%d", iterations, maxIterationCycle);

Alternativally，我曾尝试：

 
    // Set action move 
    CCAction *actionMove1 = CCCallFuncN::create(this, callfuncN_selector(GameObject::macroSetNewPoint)); 
    CCAction *actionMove2 = CCDelayTime::create(this->getSamplingPeriod()); 
    CCAction *actionMove3 = CCCallFuncN::create(this, callfuncN_selector(GameObject::updateCircle));

而且

 
     // Set action move 
    CCAction *actionMove1 = CCMoveTo::create(this->getSamplingPeriod(), _newPoint); 
    CCAction *actionMove2 = CCDelayTime::create(this->getSamplingPeriod()); 
    CCAction *actionMove3 = CCCallFuncN::create(this, callfuncN_selector(GameObject::updateCircle));

的问题是，经过1000次迭代左右，它自败，并出现在圆我的游戏对象的动作，但再过几秒钟。我不知道发生了什么 - 点正确计算（我认为）

也许moveto需要更多的时间来执行？我怎么能计算一个数学赞助人移动我的精灵之后？

来源

2012-07-22 vgonisanz

我测试了你的代码并且工作正常。请检查您是否正在更新另一个回调或其他内容。如果数据是公开的，它可能会被代码的另一部分更新。

来源

2012-08-01 09:53:32 goe

使用数学函数的值在cocos2d-x中渲染

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