0
选择值在甲骨文工作11.2如何在Oracle VARRAY
我已经创建了一个电话号码,一个类型与雇员相关.... 我想学习语法,不想成为批评好坏数据库不屑......
这里是我的* .sql文件
CREATE TYPE AddressType AS OBJECT(streetNumber NUMBER(5), StreetName VARCHAR2(30), city VARCHAR2(20));
/
CREATE TYPE empName AS OBJECT(firstname VARCHAR2(10), middle VARCHAR2(10), lastname VARCHAR2(10));
/
CREATE TYPE PhoneNumbers AS OBJECT(phNumb NUMBER(10), numType VARCHAR2(10));
/
CREATE TYPE ContactNumbers AS VARRAY(5) OF PhoneNumbers;
/
CREATE TABLE Workers(eid NUMBER(5), name empName, loc AddressType, contactNums ContactNumbers);
INSERT INTO Workers VALUES(1,
empName('Ramos', null, 'Phil'),
AddressType(123, 'A Street', 'San Diego'),
ContactNumbers(
PhoneNumbers(1234567890, 'cell'),
PhoneNumbers(2345678901, 'home')
)
);
--Display all members of workers
SELECT * FROM Workers; -- i get something here I'm ok with
--Display all the names
--SELECT (w.name.firstname||' '||w.name.middle||' '||w.name.lastname) as "Name" FROM Workers w; --this works
--Display their location
--SELECT (w.loc.streetNumber||' '||w.loc.StreetName||', '||w.loc.city) as "Location" FROM Workers w; -- this works
--Display their phone numbers
SELECT (w.contactNums(1).phNumb||' <'||w.ContactNumbers(1).numType||'>') as "Phone Numbers" FROM Workers w; -- this line I can't figure out
问:我怎样写最后SELECT
让我得到的电话号码列表?
我想我的输出看起来是这样的:
phone Numbers
-------------
1234567890 <cell>
2345678901 <home>
太棒了!所以我们必须执行与数组的联接!我会检查链接的更多信息,谢谢! – fifamaniac04
这是正确的。如果你有多个VARRAY结构,你需要一个TABLE运算符。 – gvenzl