打印使用星号的六角形图案

Question

我正在练习打印各种图案，并且卡在六角形图案中。我使用星号（*）打印它。

它应该是动态的。我已经差不多完成了它，但是仍然停留在最后部分我已经把所有部分分成几块，并且使用while循环和条件执行所有块。

sideLength = 5 

totalLength = (sideLength)*2 + (sideLength-2) 

loop =1 

while loop<=totalLength : 
    if (loop==1) or (loop==totalLength): 
     print " "*((totalLength - sideLength)//2) + "*"* sideLength + " "*((totalLength- sideLength)//2) 

    if loop>(sideLength-1) and loop<= (sideLength-1)+sideLength: 
     print "*" + " "*(totalLength-2) + "*" 

    if (loop>=1) and (loop)<(sideLength-1): 
     print " "*(sideLength- 1- loop) + "*" + " " * ((sideLength-2) + 2*(loop)) + "*" + " "*(sideLength- 1- loop) 

    if loop>((totalLength//2) + (sideLength//2)) and loop<(totalLength-1): 
     print " "*(loop - 1 - sideLength) + "*" 

    loop+=1 

从这最后如果条件发生的问题。

Answer 1

要在任意长度> 1上工作，必须更改第二个if语句。我为你解决了最后一个问题：

sideLength = 5 
totalLength = (sideLength) + 2*(sideLength-1) 

loop = 1 

while loop<=totalLength : 
    if loop==1 or loop==totalLength: 
     print " "*(sideLength-1) + "*"* sideLength + " "*(sideLength-1) 

    if loop>sideLength-1 and loop<= 2*sideLength-1: 
     print "*" + " "*(totalLength-2) + "*" 

    if loop>=1 and loop<sideLength-1: 
     print " "*(sideLength- 1- loop) + "*" + " " * ((sideLength-2) + 2*(loop)) + "*" + " "*(sideLength- 1- loop) 

    if loop>=2*sideLength-1 and loop<totalLength-1: 
     print " "*(loop-totalLength+sideLength) + "*"+ " " *(totalLength-2*(loop-totalLength+sideLength+1)) + "*" + " "*(sideLength- 1- loop) 

    loop+=1