尝试查找星号和三角形数字时未打印的代码

Question

我试图编写打印星号和三角形数字的程序的代码。虽然代码似乎没有工作，并不会打印出任何值，starNumbers的功能工作正常，但我认为三角形数的函数有点不确定，我不太确定问题出在哪里。

所有帮助将不胜感激 感谢

public class TriangularNumbers { 

    public static void main(String[] args) { 
     int n = 1; 
     int i = 1; 
     int star = starNumbers(n); 
     int triangle = triangleNumbers(i, n); 

     while (star > 0) 
     { 
      while (star < triangle) 
      { 
       n++; 
       star = starNumbers(n); 
      } 
      while (triangle < star) 
      { 
       triangle = triangleNumbers(i, n); 
      } 
      if (star==triangle) 
      { 
       System.out.println(star); 
      } 
     } 
    } 
    private static int starNumbers (int n) { 
     int s = ((6*n)*(n-1)+1); 
     return s; 
    } 
    private static int triangleNumbers(int i, int n){ 
     int star = starNumbers(n); 
     int t = 0; 
     while (t<=star) 
     { 
      t = t + i; 
      i++; 
     } 
     return t; 
    } 
} 

Answer 1

//try this 

public class TriangularNumbers { 

    public static void main(String[] args) { 
     int n = 1; 
     int i = 1; 
     int star = starNumbers(n); 
     int triangle = 0; 

     while (star > 0){ 
      star = starNumbers(n++); 
      triangle=0; 
      //System.out.println("Star "+star); 
      while(triangle < star){ 

       triangle = triangleNumbers(i,star); 

       if(star == triangle){ 
        System.out.println("match at "+star); 
       } 
      } 
     } 
    } 

    private static int starNumbers (int n) { 
     int s = ((6*n)*(n-1)+1); 
     return s; 
    } 

    private static int triangleNumbers(int i, int star){ 
     int t = 0; 
     while (t<star){ 
      t = i*(i+1)/2; //get next triangle 
      i++; 
     } 
     return t; 
    } 
} 

Answer 2

这是一个空循环：

while (star > 0); 

应该

while(star > 0) 

但是，我看到if(star==traingle)条件从来都不是是真的，所以没有看到输出。