如何优化我的查询？

我想统计接口的数量，并写出这个代码，它们从两个表节点和接口中统计出来。此代码有效，但我想知道其他方式或优化此代码？数数的最佳方法是什么？如何优化我的查询？

 

     SELECT 
    q1.NodeName, 
    q1.Nup as up, 
    q2.ndown as down 
    FROM (
    SELECT 
     Nodes.NodeID AS NodeID, 
     Interfaces.NodeID AS InterfaceID, 
     Nodes.Caption AS NodeName, 
     Interfaces.Status as Status, 
     Count(Nodes.Caption) as Nup 
     FROM 
     Nodes INNER JOIN Interfaces ON (Nodes.NodeID = Interfaces.NodeID) 
     WHERE 
     (
      (
      (Interfaces.Status = '2')) 
     ) 
     GROUP BY Nodes.NodeID, Nodes.Caption, Interfaces.Status, Interfaces.NodeID 
    ) AS q1 
    INNER JOIN (
SELECT 
Interfaces.NodeID AS InterfaceID, 
Nodes.Caption AS NodeName, 
Interfaces.Status as Status, 
Count(Nodes.Caption) as ndown 
FROM 
Nodes INNER JOIN Interfaces ON (Nodes.NodeID = Interfaces.NodeID) 
WHERE 
(
    (
    (Interfaces.Status = '1')) 
) 

GROUP BY Nodes.NodeID, Nodes.Caption, Interfaces.Status, Interfaces.NodeID 

    ) AS q2 

ON (q1.NodeID = q2.InterfaceID) 
order by down Desc

来源

2011-03-04 user453949

你有什么指数？你的桌子结构是什么？ – JNK 2011-03-04 20:10:31

哪个SQL ... SQL-Server，Oracle，MySQL ??? – DRapp 2011-03-04 20:11:56

sql server 2005 – user453949 2011-03-05 05:10:13

您可以组合查询：

SELECT 
    Nodes.Caption AS NodeName, 
    Count(
     CASE WHEN Interfaces.Status = '2' 
     THEN 1 
     ELSE NULL 
     END) as up, 
    Count(
     CASE WHEN Interfaces.Status = '1' 
     THEN 1 
     ELSE NULL 
     END) as down 
FROM Nodes 
    INNER JOIN Interfaces ON (Nodes.NodeID = Interfaces.NodeID) 
WHERE Interfaces.Status IN('1', '2') 
GROUP BY Nodes.NodeID, Nodes.Caption 
order by 3 Desc

注意：您原来的查询，如果接口始终处于up，或总是下跌，也不会在结果中显示，因为你正在使用一个INNER JOIN。

来源

2011-03-04 20:13:39

+1击败我。 – 2011-03-04 20:14:31

我会简化接口上的内部查询，因为这是WHERE的整个基础，直到THAT结果集完成后才需要连接到节点，那么一旦单个节点完成，就连接到节点。

SELECT 
     Nodes.NodeName, 
     Q1.CountUp as Up, 
     Q1.CountDown as Down 
    FROM 
     (SELECT 
       Interfaces.NodeID AS InterfaceID, 
       SUM(CASE WHEN Interfaces.Status = '1' then 1 else 0 end) as CountUp, 
       SUM(CASE WHEN Interfaces.Status = '2' then 1 else 0 end) as CountDown 
      FROM 
       Interfaces 
      WHERE 
       Interfaces.Status IN ('1','2') 
      GROUP BY 
       1) AS q1 
     INNER JOIN Nodes 
     ON q1.NodeID = Nodes.NodeID 
    order by 
     3 desc

来源

2011-03-04 20:23:23 DRapp

如何优化我的查询？

回答

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