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我其实是建立一个简单的网站会员,我想通过只调用http://www.mywebsite.com/member/membername显示会员页面问题与CI构造函数和URI
我的类成员实际工作很好,但我已经把代码中索引功能使得页面成员可以在http://www.mywebsite.com/member/index/membername访问,这实际上并不真正有用。
所以经典的东西是把我的代码在构造函数中,但我得到的错误:
404找不到页面 您请求的页面不存在。
这是我的类成员:
<?php
class Member extends CI_Controller {
function __construct()
{
parent::__construct();
$segment_id = $this->uri->segment(2, 0);
echo 'segment found ='.$segment_id;
if ($segment_id == FALSE)
{
echo '- No Segment -> Printing all members ';
$data = array();
$this->layouts->set_title('Welcome!');
$this->layouts->add_aside('newsletter_view');
if($query = $this->membership_model->show_all())
{
$data['records'] = $query;
}
$this->layouts->view('show_member', $data);
}
else
{
echo '- Segment found -> Printing the member ';
$data = array();
$this->layouts->set_title('Welcome!');
$this->layouts->add_aside('newsletter_view');
if($query = $this->membership_model->show_member())
{
$data['records'] = $query;
}
$this->layouts->view('show_member', $data);
}
}
}
并完成,这是我的模型功能:
function show_member()
{
echo 'model show_member working';
$this->db->where('username', $this->uri->segment(2));
$query = $this->db->get('members');
return $query->result();
}
function show_all()
{
echo "model show_all working";
$query = $this->db->get('members');
return $query->result();
}
你会发现一些呼应成。所有完美的工作与/或会员/会员/段和我伤心的一个网址去,所有的工作,如果我把它在指数
非常感谢您的帮助
回答于:http://codeigniter.com/forums/viewthread/187548/ – v1ctoria 2011-04-27 17:40:37