我正在编写一个简单的CASE来在员工获得更多的部门AVG工资时在屏幕上打印。但是我不明白为什么我在屏幕上看到只有一个结果,当我想检查2名员工的工资时。我希望你能理解我的问题。谢谢。关于PLSQL的CASE语句有什么问题?
SET SERVEROUTPUT ON
DECLARE
v_emp121_sal employees.salary%TYPE;
v_emp121_lname employees.last_name%TYPE;
v_emp139_sal employees.salary%TYPE;
v_emp139_lname employees.last_name%TYPE;
v_avgsal employees.salary%TYPE;
BEGIN
SELECT salary, last_name
INTO v_emp121_sal, v_emp121_lname
FROM employees
WHERE employee_id = 121;
DBMS_OUTPUT.PUT_LINE('EMPLOYEE 121 SALARY IS: ' || v_emp121_sal);
SELECT salary, last_name
INTO v_emp139_sal, v_emp139_lname
FROM employees
WHERE employee_id = 139;
DBMS_OUTPUT.PUT_LINE('EMPLOYEE 139 SALARY IS: ' || v_emp139_sal);
SELECT AVG(salary)
INTO v_avgsal
FROM employees
WHERE department_id = 50;
DBMS_OUTPUT.PUT_LINE('DEPARTMENT 50 AVG SALARY IS: ' ||
TRUNC(v_avgsal, 0));
CASE
WHEN
v_emp121_sal < v_avgsal THEN
DBMS_OUTPUT.PUT_LINE('SALARY OF EMP ' || v_emp121_lname ||
' IS LESS THAN DEPARTMENT AVG');
WHEN
v_emp121_sal > v_avgsal THEN
DBMS_OUTPUT.PUT_LINE('SALARY OF EMP ' || v_emp121_lname ||
' IS HIGHER THAN AVG DEPARTMENT');
WHEN
v_emp139_sal < v_avgsal THEN
DBMS_OUTPUT.PUT_LINE('SALARY OF EMP ' || v_emp139_lname ||
' IS LESS THAN DEPARTMENT AVG');
WHEN
v_emp139_sal > v_avgsal THEN
DBMS_OUTPUT.PUT_LINE('SALARY OF EMP ' || v_emp139_lname ||
' IS HIGHER THAN AVG DEPARTMENT');
END CASE;
END;
/
理论,我应该接受在屏幕上 “EMP抚顺石油化工研究院的工资比AVG DEPARTMENT较高的” “EMP SEO的工资比AVG DEPARTMENT LESS”
工资NUMBER(8,2) – Rattlesnake
'响尾蛇'..你可以在这里发布你的工作代码供其他人参考 – XING