岩纸剪刀简单的java使用方法

Question

所以我今天的任务是使用方法做一个石头纸剪刀游戏。我的代码的第一个问题是，我需要它来询问用户是否要再次玩。 （y或n）另外，我需要实现得分，如果用户获胜，则得1分，如果失败，则为-1，并且每次他们再次玩都将该得分添加到总得分。关于如何实现这个的任何想法？或者我需要更改为我的代码。另外，我是一个新手，对于丑陋的格式感到抱歉，并随时批评每一个小细节，因此我不能吸收所有可能的信息。

public static void main(String[] args){ 
boolean tie = true; 
    do{ 
     String computer = computerChoice(); 
     String user = userChoice(); 
     tie = (computer.compareTo(user) == 0); 
     determineWinner(computer, user); 
    }while(tie); 

    } 

    public static String computerChoice(){ 
    Random rand = new Random(); 
int cinput = rand.nextInt(3)+ 1; 
    String computer = "thing"; 
    if (cinput == 1) 
    computer = "Rock"; 
    if (cinput == 2) 
    computer = "Paper"; 
if (cinput == 3) 
    computer = "Scissors"; 
    return computer; 
    } 
    public static String userChoice(){ 
    Scanner sc = new Scanner (System.in); 
    String user = "default"; 
    do{ 
    System.out.println("choose your weapon(Paper,Scissors or Rock)"); 
    user = sc.nextLine(); 
    } 
    while (isValidChoice (user) == false); 
    return user; 
    } 
    public static boolean isValidChoice(String choice){ 
    boolean status; 
    if (choice.compareTo("Rock")== 0) 
    status = true; 
    else if (choice.compareTo("Paper")== 0) 
    status = true; 
    else if (choice.compareTo("Scissors")== 0) 
    status = true; 
    else{ 
    status = false; 
    System.out.println("Error! Make sure you are capitalizing your     choices"); 
} 

return status; 
    } 
    public static boolean determineWinner(String computer, String user){ 
    System.out.println (" Computer Choice: " + computer); 
    System.out.println ("Your Choice : " + user); 
    if (computer.compareTo("Rock") == 0 && user.compareTo ("Scissors") == 0) 
    System.out.println (" Computer wins! Better luck next time!"); 
    if (computer.compareTo("Scissors")== 0 && user.compareTo("Paper") == 0) 
    System.out.println (" Computer wins! Better luck next time!"); 
    if (computer.compareTo("Paper") == 0 && user.compareTo("Rock") == 0) 
    System.out.println (" Computer wins! Better luck next time!"); 
    if (computer.compareTo("Rock") == 0 && user.compareTo("Paper") == 0) 
    System.out.println (" You win!!"); 
    if (computer.compareTo("Scissors") == 0 && user.compareTo("Rock") == 0) 
    System.out.println (" You win!!"); 
    if (computer.compareTo("Paper") == 0 && user.compareTo("Scissors") == 0) 
    System.out.println (" You win!!"); 
    else if (computer.compareTo(user) == 0){ 
    System.out.println(" Tie! the game must be played again."); 
    return false; 
    } 
    return true; 
} 
} 

，我的教授给我们作为一个例子输出为：

Choose your weapon! 
1. Paper 
2. Scissors 
3. Rock 
5 
Choose your weapon! 
1. Paper 
2. Scissors 
3. Rock 
    1 
You chose paper! 
I choose rock! 
I have been vanquished! 
We have matched wits 1 times, and your score is 1 
Do you want to play again (y or n)? y 
Choose your weapon! 
1. Paper 
2. Scissors 
3. Rock 
1 
You chose paper! 
    I choose paper! 
    We are equally matched. You are a worthy adversary. 
    We have matched wits 2 times, and your score is 1 
    Do you want to play again (y or n)? n 

Answer 1

这里是最终的程序代码。我添加了两个函数，一个用于调用实际游戏，另一个用于检查玩家是否想再次玩。另外，最后还有最后一句话

import java.util.Random; 
import java.util.Scanner; 

public class RPC 
{ 
    public static Scanner sc   = new Scanner(System.in); 
    public static int  score  = 0; 
    public static int  gameCount = 0; 

    public static void main(String[] args) 
    { 
     play(); 
     while (playAgain()) 
     { 
      play(); 
     } 
    } 

    public static void play() 
    { 
     String computer = computerChoice(); 
     String user = userChoice(); 
     determineWinner(computer, user); 
    } 

    public static String computerChoice() 
    { 
     Random rand = new Random(); 
     int cinput = rand.nextInt(3) + 1; 
     String computer = "thing"; 
     if (cinput == 1) 
      computer = "Rock"; 
     if (cinput == 2) 
      computer = "Paper"; 
     if (cinput == 3) 
      computer = "Scissors"; 
     return computer; 
    } 

    public static boolean playAgain() 
    { 
     System.out.println("Play again?(y/n)"); 
     String input = sc.nextLine(); 
     if (input.toLowerCase().equals("y")) 
     { 
      return true; 
     } else if (input.toLowerCase().equals("n")) 
     { 
      return false; 
     } else 
     { 
      System.out.println("Invalid Input"); 
      return playAgain(); 
     } 

    } 

    public static String userChoice() 
    { 

     String user = "default"; 
     do 
     { 
      System.out.println("choose your weapon(Paper,Scissors or Rock)"); 
      user = sc.nextLine(); 
     } while (!isValidChoice(user)); 
     return user; 
    } 

    public static boolean isValidChoice(String choice) 
    { 
     boolean status; 
     if (choice.equals("Rock")) 
      status = true; 
     else if (choice.equals("Paper")) 
      status = true; 
     else if (choice.equals("Scissors")) 
      status = true; 
     else 
     { 
      status = false; 
      System.out.println("Error! Make sure you are capitalizing your choices"); 
     } 

     return status; 
    } 

    public static void determineWinner(String computer, String user) 
    { 
     gameCount++; 
     System.out.println(" Computer Choice: " + computer); 
     System.out.println("Your Choice : " + user); 
     if (computer.equals("Rock") && user.equals("Scissors")) 
     { 
      score--; 
      System.out.println(" Computer wins! Better luck next time!"); 
     } 
     if (computer.equals("Scissors") && user.equals("Paper")) 
     { 
      score--; 
      System.out.println(" Computer wins! Better luck next time!"); 
     } 
     if (computer.equals("Paper") && user.equals("Rock")) 
     { 
      score--; 
      System.out.println(" Computer wins! Better luck next time!"); 
     } 
     if (computer.equals("Rock") && user.equals("Paper")) 
     { 
      score++; 
      System.out.println(" You win!!"); 
     } 
     if (computer.equals("Scissors") && user.equals("Rock")) 
     { 
      score++; 
      System.out.println(" You win!!"); 
     } 
     if (computer.equals("Paper") && user.equals("Scissors")) 
     { 
      score++; 
      System.out.println(" You win!!"); 
     } else if (computer.equals(user)) 
     { 
      System.out.println(" Tie! the game must be played again."); 
     } 
     System.out.println("We have matched wits" + gameCount + "times, and your score is" + score); 
     return; 
    } 

}