这是我猜想的理论。实例访问继承的抽象类成员
不应该Main()有权访问_XLocal & _YLocal?
using System;
namespace HelloGoodbyeOperator {
public abstract class HGOperator {
public string _greeting { get; set; }
public bool _x { get; internal set; }
public bool _y { get; internal set; }
public static implicit operator HGOperator(bool mode) {
object ret = new object();
if (mode)
ret = new HGOperator_Hello { _greeting = "hello", _XLocal = 10 };
else
ret = new HGOperator_Goodbye { _greeting = "goodbye", _YLocal = 20 };
return (HGOperator)ret;
}
}
public class HGOperator_Hello : HGOperator {
public int _XLocal { get; set; }
public HGOperator_Hello() { _x = true; Console.WriteLine("HGOperator_Hello //" + _XLocal.ToString() + "\\\\"); }
}
public class HGOperator_Goodbye : HGOperator {
public int _YLocal { get; set; }
public HGOperator_Goodbye() { _y = false; Console.WriteLine("HGOperator_Goodbye //", _YLocal, "\\\\"); }
}
class Program {
static void Main(string[] args) {
HGOperator hg = true;
Console.WriteLine(hg._greeting);
test(hg);
Console.WriteLine("");
hg = false;
Console.WriteLine(hg._greeting);
test(hg);
Console.ReadKey();
}
static void test(HGOperator hg) {
if (hg is HGOperator_Hello) {
Console.WriteLine(hg._x);
//Console.WriteLine(hg._XLocal);
} else {
Console.WriteLine(hg._y);
//Console.WriteLine(hg._YLocal);
}
}
}
}
这里是输出
HGOperator_Hello // 0 \
你好
真
HGOperator_Goodbye //
再见
假
我能理解如何试图访问一个HGOperator_Hello类型的hg._YLocal将是一场噩梦&反之亦然。但是仍然会认为我可以谨慎地向各个成员求助。
此外,我敢打赌,这是真实的。这两个具体构造函数在Console.Writeline()中没有_XLocal的值_YLocal。没有.ToString()只打印一个“”。为什么不? 谢谢。
其中是'Main'?什么是问题? –
@GlennFerrie永远在哪里。大声笑。 'class Program {static void Main(string [] args){' – Steve