PHP数组计数时，ID和可变匹配

Question

晚上好，

我打破我的头以下... 我得到多数民众赞成计算有多少场比赛有像所有其他信息都起到了脚本，点，进球，进球对你..

但我也想知道有多少匹配的球队都赢得/平局的目标/丢失等

我只是不能似乎得到它。 数据库中的表，我得到了以下字段名为

(homePoints, awayPoints, homeResult, awayResult) 
(3,   0,   win,  lose) 

这是我得到返回的数组的一部分：

2 => 
    array (size=7) 
     'TeamID' => string '1' (length=1) 
     'Matches' => string '1' (length=1) 
     'GoalsVoor' => string '2' (length=1) 
     'GoalsTegen' => string '0' (length=1) 
     'DoelSaldo' => int 2 
     'Punten' => string '3' (length=1) 
     'MatchResult' => string 'win' (length=3) 
    3 => 
    array (size=7) 
     'TeamID' => string '1' (length=1) 
     'Matches' => string '2' (length=1) 
     'GoalsVoor' => string '2' (length=1) 
     'GoalsTegen' => string '7' (length=1) 
     'DoelSaldo' => int -5 
     'Punten' => string '0' (length=1) 
     'MatchResult' => string 'lose' (length=4) 

现在，当你看到TeamID是匹配，但MatchResults麦凯纳吨，我想或者使一个子阵列像

TeamID => 1 
MatchesWon => 1 and adding if the win more. 
MatchesLost => 1 and adding if they lose more. 
MatchesDraw => 0 and adding if they draw more. 

但不能弄明白。

任何帮助，将不胜感激。

亲切的问候， 帕特里克

Answer 1

继承人我会做什么

$teams = array(); // Empty array for your teams 
$results = array('wins' => 0, 'draws' => 0, 'losses' = 0); // Starting array for each team 
foreach ($array as $a) { // Loop over your database array 
    $id = $a['TeamID']; // Use TeamID as your array keys 
    if (!isset($teams[$id])) { // Check if team is already in your teams array 
     $teams[$id] = $results; // If not then insert them with the starting array 
    } 
    if ($a['Punten'] == 0) {   // Now loop over the points column and increment results 
     $teams[$id]['losses'] += 1; 
    } 
    if ($a['Punten'] == 1) { 
     $teams[$id]['draws'] += 1; 
    } 
    if ($a['Punten'] == 3) { 
     $teams[$id]['wins'] += 1; 
    } 
}