结合PHP数组，与匹配值

Question

我有一组PHP阵列

$arrayOne = (
    0 => new, 
    1 => old, 
    2 => fresh, 
    3 => new, 
    4 => old, 
    5 => fresh, 
    6 => new, 
    7 => old, 
    8 => fresh, 

    ) 
$arrayTwo = (
    0 => yellow, 
    1 => green, 
    2 => red, 
    3 => blue, 
    4 => grey, 
    5 => orange, 
    6 => purple, 
    7=> pink, 
    8 => brown 
    ) 
$arrayThree = (
    0 => Monday 
    1 => Tuesday 
    2 => Wednesday 
    3 => Thursday 
    4 => Friday 
    5 => Saturday 
    6 => Sunday 
    7 => Monday2 
    8 => Monday3 
) 

这些阵列的被虽然环状，并放置在一个表

for($index = 0; index < 100; $index++){ 

$returnVariable .= '<td>'.$ArrayOne[$index].'</td>'; 
$returnVariable .= '<td>'.$ArrayTwo[$index].'</td>'; 
$returnVariable .= '<td>'.$ArrayThree[$index].'</td>'; 

}

当返回和显示在页面上，表格的工作原理与所有匹配的方式一致

new yellow monday 
old green  tuesday 
fresh red  wednesday 

等等，等等，我想小组第一列，以便它列出所有的“新”，那么所有的“老字号”，那么所有的新鲜，同时保持预期的匹配前，

new yellow  monday 
new blue  thursday 
new purple  sunday 
old green  tuesday 
old grey  friday 
old pink  Monday2 

等etc

Answer 1

首先，将三个数组合并成一个。然后，排序由所述第一值的新阵列（新的第一，然后旧，则新鲜）：

<?php  
$arrayOne = [ 
    0 => "new", 
    1 => "old", 
    2 => "fresh", 
    3 => "new", 
    4 => "old", 
    5 => "fresh", 
    6 => "new", 
    7 => "old", 
    8 => "fresh", 

]; 
$arrayTwo = [ 
    0 => "yellow", 
    1 => "green", 
    2 => "red", 
    3 => "blue", 
    4 => "grey", 
    5 => "orange", 
    6 => "purple", 
    7=> "pink", 
    8 => "brow" 
]; 
$arrayThree = [ 
    0 => "Monday", 
    1 => "Tuesday", 
    2 => "Wednesday", 
    3 => "Thursday", 
    4 => "Friday", 
    5 => "Saturday", 
    6 => "Sunday", 
    7 => "Monday2", 
    8 => "Monday3", 
]; 
echo "<pre>"; 
for ($i = 0; $i < count($arrayOne); $i++) { 
    $array[] = [ 
     $arrayOne[$i], 
     $arrayTwo[$i], 
     $arrayThree[$i], 
    ]; 
} 
$values = [ // give these strings a numeric value to compare them 
    "new" => 0, 
    "old" => 1, 
    "fresh" => 2, 
]; 
usort($array, function($a, $b) use ($values) { 
    return $values[$a[0]] - $values[$b[0]]; 
}); 

Demo

Answer 2

Create new array to hold all then sort it and implode it into a string 
    <?php 
    $arrayOne = array(
     0 => "new", 
     1 => "old", 
     2 => "fresh", 
     3 => "new", 
     4 => "old", 
     5 => "fresh", 
     6 => "new", 
     7 => "old", 
     8 => "fresh", 

     ); 
    $arrayTwo = array(
     0 => "yellow", 
     1 => "green", 
     2 => "red", 
     3 => "blue", 
     4 => "grey", 
     5 => "orange", 
     6 => "purple", 
     7=> "pink", 
     8 => "brown" 
     ); 
    $arrayThree =array(
     0 => "Monday", 
     1 => "Tuesday", 
     2 => "Wednesday", 
     3 => "Thursday", 
     4 => "Friday", 
     5 => "Saturday", 
     6 => "Sunday", 
     7 => "Monday2", 
     8 => "Monday3" 
    ); 
    $returnVariable=array(); 
    for($index = 0; $index<count($arrayOne); $index++){ 

    $returnVariable[$index][0]= '<td>'.$arrayOne[$index].'</td>'; 
    $returnVariable[$index][1]= '<td>'.$arrayTwo[$index].'</td>'; 
    $returnVariable[$index][2]= '<td>'.$arrayThree[$index].'</td>'; 

    } 
    sort($returnVariable); 
    echo "<table>"; 
    for ($i=0; $i<count($returnVariable); $i++) { 
      if (@is_array($returnVariable[$i])) 
       $returnVariable[$i] = implode($returnVariable[$i]," "); 
    echo "<tr>"; 

     print $returnVariable[$i]; 
     echo "</tr>"; 

    } 
    echo "</table>"; 

Answer 3

直向前溶液：

$arrayOne = array(0 => "new",1 => "old",2 => "fresh",3 => "new",4 => "old",5 => "fresh",6 => "new",7 => "old",8 => "fresh",); 
$arrayTwo = array(0 => "yellow",1 => "green",2 => "red",3 => "blue",4 => "grey",5 => "orange",6 => "purple",7=> "pink",8 => "brown"); 
$arrayThree = array(0 => "Monday",1 => "Tuesday",2 => "Wednesday",3 => "Thursday",4 => "Friday",5 => "Saturday",6 => "Sunday",7 => "Monday2",8 => "Monday3"); 

$result = []; 
foreach($arrayOne as $k => $v){ 
    $result[$v][] = "<tr><td>$v</td><td>{$arrayTwo[$k]}</td><td>{$arrayThree[$k]}</td></tr>"; 
} 

echo '<table>'; 
foreach(['new', 'old', 'fresh'] as $k){ 
    echo implode("", $result[$k]); 
} 
echo '</table>'; 

输出（按“运行代码片段”）：

<table border="1"><tr><td>new</td><td>yellow</td><td>Monday</td></tr><tr><td>new</td><td>blue</td><td>Thursday</td></tr><tr><td>new</td><td>purple</td><td>Sunday</td></tr><tr><td>old</td><td>green</td><td>Tuesday</td></tr><tr><td>old</td><td>grey</td><td>Friday</td></tr><tr><td>old</td><td>pink</td><td>Monday2</td></tr><tr><td>fresh</td><td>red</td><td>Wednesday</td></tr><tr><td>fresh</td><td>orange</td><td>Saturday</td></tr><tr><td>fresh</td><td>brown</td><td>Monday3</td></tr></table>

Answer 4

另一种方式来做到这一点是

$row =""; 
$temp = array(); 
foreach($arrayOne as $key => $value){ 
    $temp[$value][] = $key; 
} 
foreach($temp as $value){ 
    foreach($value as $value2){ 
    $row .= ' '.$arrayOne[$value2].''; 
    $row .= ' '.$arrayTwo[$value2].''; 
    $row .= ' '.$arrayThree[$value2]."\n"; 
    } 
} 
echo $row; 

现场演示：https://eval.in/850007