我有下面的代码将32位BCD值(以两个半角提供)转换为uint二进制值。将BCD转换为二进制的最有效方法
提供的值可以高达0x9999,以形成最大值0x99999999。
有没有更好的(即更快)的方式来实现这一目标?
/// <summary>
/// Convert two PLC words in BCD format (forming 8 digit number) into single binary integer.
/// e.g. If Lower = 0x5678 and Upper = 0x1234, then Return is 12345678 decimal, or 0xbc614e.
/// </summary>
/// <param name="lower">Least significant 16 bits.</param>
/// <param name="upper">Most significant 16 bits.</param>
/// <returns>32 bit unsigned integer.</returns>
/// <remarks>If the parameters supplied are invalid, returns zero.</remarks>
private static uint BCD2ToBin(uint lower, uint upper)
{
uint binVal = 0;
if ((lower | upper) != 0)
{
int shift = 0;
uint multiplier = 1;
uint bcdVal = (upper << 16) | lower;
for (int i = 0; i < 8; i++)
{
uint digit = (bcdVal >> shift) & 0xf;
if (digit > 9)
{
binVal = 0;
break;
}
else
{
binVal += digit * multiplier;
shift += 4;
multiplier *= 10;
}
}
}
return binVal;
}
看起来相当好给我。 – Spence 2009-01-20 20:38:00
为什么需要两个提示而不是ushorts,如果每个只代表16位? – 2009-01-20 20:38:44