2011-07-19 40 views
1

Post.find(:all, :select => "DISTINCT author")
return
[#<Post author: nil>, #<Post author: nil>, #<Post author: nil>, #<Post author: nil>, #<Post author: nil>]select distinct returns nil(globalize3)

但SQL请求SELECT DISTINCT author FROM posts;按预期工作。

我正在使用globalize3。 Post.select('DISTINCT author').with_translations('en')返回所有记录。
下面是它的日志中:

Post Load (0.5ms) SELECT "posts"."id" AS t0_r0, "posts"."description" AS t0_r1, "posts"."position" AS t0_r2, "posts"."created_at" AS t0_r3, "posts"."updated_at" AS t0_r4, "posts"."date" 
AS t0_r5, "post_translations"."id" AS t1_r0, "post_translations"."post_id" AS t1_r1, "post_translations"."locale" AS t1_r2, "post_translations"."author" 
AS t1_r3, "post_translations"."description" AS t1_r4, "post_translations"."created_at" AS t1_r5, "post_translations"."updated_at" 
AS t1_r6 FROM "posts" LEFT OUTER JOIN "post_translations" ON "post_translations"."post_id" = "posts"."id" WHERE "post_translations"."locale" = 'en' 
AND (post_translations.author IS NOT NULL) 

我怎么可以只选择不同的值?

+0

请发表日志块用两个请求 – Bohdan

+0

已更新。这是第一个请求:'ActionView :: Template :: Error(No route matches {:action =>“show”,:controller =>“posts”,:id =>#}):' – NARKOZ

回答

0

可能是这个简单:

Post.find(:all, :group => author) 

更新:

貌似Postgres的是一个小比MySQL更柔顺,所以尝试这个:

Post.select("DISTINCT ON (author) *") 
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'Post load(0.5ms)SELECT“posts”。* FROM“posts”WHERE(post_category_id = 1)GROUP BY作者 PGError:错误:列“posts.id”必须出现在GROUP BY子句中或用于汇总函数 LINE 1:SELECT“posts”。* FROM“posts”WHERE(post_category_id = 1)G ...' – NARKOZ

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增加了postgres解决方案,修复了由bug –

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thx组的bug, – NARKOZ