更新的DataSet加caclulated领域

Question

我有一个数据集见下图：

SELECT jockey.jockey_skey 
, raceresults.place 
FROM jockey 
     INNER JOIN runnersandriders 
       ON jockey.jockey_skey = runnersandriders.jockey_skey 
     INNER JOIN horse 
       ON runnersandriders.horse_skey = horse.horse_skey 
     INNER JOIN raceresults 
       ON horse.horse_skey = raceresults.horse_skey 
GROUP BY jockey.jockey_skey, 
      raceresults.place 
ORDER BY jockey.jockey_skey 

这为我提供了：

Jockey_Skey Place 
1    01 
1    04 
2    03 
2    04 
3    02 
3    02 

我想要做的就是算一个赛马有多少场比赛跑和他们来的清单。

因此，骑师1，赛程2次，第一次和第四次如此如此，但对于我的生活，我不记得如何去做。

我希望你能帮上忙。

感谢

W¯¯

Answer 1

你可以使用这样的事情让每个骑师的结果一行：

SELECT jockey.jockey_skey, 
     TotalRaces = COUNT(*), 
     [1sts] = COUNT(CASE WHEN raceresults.place = '01' THEN 1 END), 
     [2nds] = COUNT(CASE WHEN raceresults.place = '02' THEN 1 END), 
     [3rds] = COUNT(CASE WHEN raceresults.place = '03' THEN 1 END), 
     [4ths] = COUNT(CASE WHEN raceresults.place = '04' THEN 1 END), 
     [5ths] = COUNT(CASE WHEN raceresults.place = '05' THEN 1 END), 
     [6ths] = COUNT(CASE WHEN raceresults.place = '06' THEN 1 END), 
     [7ths] = COUNT(CASE WHEN raceresults.place = '07' THEN 1 END), 
     [8ths] = COUNT(CASE WHEN raceresults.place = '08' THEN 1 END), 
     -- etc 
     [NonRunner] = COUNT(CASE WHEN raceresults.place = 'NR' THEN 1 END), 
     [Fell] = COUNT(CASE WHEN raceresults.place = 'F' THEN 1 END), 
     [PulledUp] = COUNT(CASE WHEN raceresults.place = 'PU' THEN 1 END), 
     [Unseated] = COUNT(CASE WHEN raceresults.place = 'U' THEN 1 END), 
     [Refused] = COUNT(CASE WHEN raceresults.place = 'R' THEN 1 END), 
     [BroughtDown] = COUNT(CASE WHEN raceresults.place = 'B' THEN 1 END) 
FROM jockey 
     INNER JOIN runnersandriders 
      ON jockey.jockey_skey = runnersandriders.jockey_skey 
     INNER JOIN horse 
      ON runnersandriders.horse_skey = horse.horse_skey 
     INNER JOIN raceresults 
      ON horse.horse_skey = raceresults.horse_skey 
GROUP BY jockey.jockey_skey 
ORDER BY jockey.jockey_skey 

Simplified Example on SQL Fiddle

另外，您可以使用WITH ROLLUP获得总计额外的一行：

SELECT jockey.jockey_skey, 
     raceresults.place, 
     [CountOfResult] = COUNT(*) 
FROM jockey 
     INNER JOIN runnersandriders 
      ON jockey.jockey_skey = runnersandriders.jockey_skey 
     INNER JOIN horse 
      ON runnersandriders.horse_skey = horse.horse_skey 
     INNER JOIN raceresults 
      ON horse.horse_skey = raceresults.horse_skey 
GROUP BY jockey.jockey_skey, raceresults.place 
WITH ROLLUP 
ORDER BY jockey.jockey_skey, raceresults.place; 

凡NULL值代表共计

Simplified Example on SQL Fiddle