组合2个SQL查询

Question

我被困在SQL问题上，我几乎可以肯定这很容易，但我找不到合适的答案。下面是这个例子。我想那些2个查询组合：

SELECT 
    num_rata, SUM(val_imp*0.01) AS amount 
FROM table1 
WHERE 
    col1 <> 0 
    AND num_contract = 88 
GROUP BY num_rata 

返回类似：

1 215.00 
2 220.00 
3 210.00 
4 115.00 
5 315.00 

和：

SELECT 
    num_rata, SUM(val_ban*0.01) AS amount 
FROM table2 
WHERE 
    num_contract = 2988 
GROUP BY num_rata; 

示例结果集：

1 15.00 
2 615.00 
3 275.00 
4 285.00 
5 285.00 
6 275.00 
7 260.00 
8 215.00 
9 215.00 

作为最后一个结果我想要一些东西e此：

1 215.00 15.00 
2 220.00 615.00 
3 210.00 275.00 
4 115.00 285.00 
5 315.00 285.00 
6   275.00 
7   260.00 
8   215.00 
9   215.00 

谢谢你的任何提示。

fabien。

Answer 1

你可以使用一个工会或外部联接 - 我宁愿工会，像这样：

SELECT num_rata, sum(val_imp)*0.01 imp_amount, sum(val_ban)*0.01 ban_amount 
from (SELECT num_rata, val_imp, 0 val_ban 
     FROM table1 
     WHERE col1 <> 0 AND num_contract = 88 
     UNION ALL 
     SELECT num_rata, 0 val_imp, val_ban 
     FROM table2 
     WHERE num_contract = 2988) v 
GROUP BY num_rata; 

Answer 2

可尝试将这种做：

SELECT num_rata, (
    coalesce(
     (SELECT SUM(val_imp*0.01) FROM table1 t1 WHERE t1.num_rata = foo.num_rata) 
    ,0) 
) as col1, (
    coalesce(
     (SELECT SUM(val_ban*0.01) FROM table2 t2 WHERE t2.num_rata = foo.num_rata) 
    ,0) 
) as col2 FROM 
(
    (SELECT num_rata FROM table1 WHERE col1 <> 0 AND num_contract = 88) 
    UNION ALL 
    (SELECT num_rata FROM table2 WHERE num_contract = 2988) 
) as foo; 

我可能有语法错误（我从一所大学演讲写这个），不过这（或类似）应该做的伎俩。

Answer 3

我想这是你想要的东西：

select 
    t1.num_rata, 
    SUM(t1.val_imp*0.01) AS amount1, 
    SUM(t2.val_ban*0.01) AS amount2 
from 
    table1 t1 right outer join table2 t2 on t1.num_rata=t2.num_rata 
where 
    t1.col1<>0 and 
    t1.num_contract = 88 and 
    t2.num_contract = 2988 
GROUP BY t1.num_rata