5
为了熟悉哈斯克尔STM，我写了下面的解决哲学家就餐问题：以下解决方案“Dining Philosophers”有什么问题？
import Control.Concurrent
import Control.Concurrent.STM
import Control.Monad
import System.Random
type Fork = TVar Bool
type StringBuffer = TChan String
philosopherNames :: [String]
philosopherNames = map show ([1..] :: [Int])
logThinking :: String -> StringBuffer -> STM()
logThinking name buffer = writeTChan buffer $ name ++ " is thinking..."
logEating :: String -> StringBuffer -> STM()
logEating name buffer = writeTChan buffer $ name ++ " is eating..."
firstLogEntry :: StringBuffer -> STM String
firstLogEntry buffer = do empty <- isEmptyTChan buffer
if empty then retry
else readTChan buffer
takeForks :: Fork -> Fork -> STM()
takeForks left right = do leftUsed <- readTVar left
rightUsed <- readTVar right
if leftUsed || rightUsed
then retry
else do writeTVar left True
writeTVar right True
putForks :: Fork -> Fork -> STM()
putForks left right = do writeTVar left False
writeTVar right False
philosopher :: String -> StringBuffer -> Fork -> Fork -> IO()
philosopher name out left right = do atomically $ logThinking name out
randomDelay
atomically $ takeForks left right
atomically $ logEating name out
randomDelay
atomically $ putForks left right
randomDelay :: IO()
randomDelay = do delay <- getStdRandom(randomR (1,3))
threadDelay (delay * 1000000)
main :: IO()
main = do let n = 8
forks <- replicateM n $ newTVarIO False
buffer <- newTChanIO
forM_ [0 .. n - 1] $ \i ->
do let left = forks !! i
right = forks !! ((i + 1) `mod` n)
name = philosopherNames !! i
forkIO $ forever $ philosopher name buffer left right
forever $ do str <- atomically $ firstLogEntry buffer
putStrLn str
当我编译和运行我的解决方案，似乎不存在明显的并发问题：每个哲学家会最终吃掉，没有哲学家似乎被青睐。但是，如果我从philosopher删除randomDelay声明，编译和运行，我的程序的输出如下所示：
1 is thinking...
1 is eating...
1 is thinking...
1 is eating...
2 is thinking...
2 is eating...
2 is thinking...
2 is eating...
2 is thinking...
2 is eating...
2 is thinking...
About 2500 lines later...
2 is thinking...
2 is eating...
2 is thinking...
3 is thinking...
3 is eating...
3 is thinking...
3 is eating...
And so on...
什么在这种情况下是怎么回事？
如果这是家庭作业，请添加作业选项卡。 – Gray
这不是作业，我在真实世界的Haskell上看过STM，我正在努力熟悉它。 – Alexandros
与我的设置（Debian 6 Testing，ghc 7.4.1，runhaskell/ghc -O2 --make philosophers.hs）我认为我没有问题 - 哲学家1.8正在进食和思考每个轮到它。你的ghc版本是什么，你正在编译或使用ghci吗？ – epsilonhalbe