使用迭代器遍历列表？

Question

我需要使用C++遍历列表的示例。

Answer 1

有关问题的示例如下

#include <iostream> 
    #include <list> 
    using namespace std; 

    typedef list<int> IntegerList; 
    int main() 
    { 
     IntegerList intList; 
     for (int i = 1; i <= 10; ++i) 
     intList.push_back(i * 2); 
     for (IntegerList::const_iterator ci = intList.begin(); ci != intList.end(); ++ci) 
     cout << *ci << " "; 
     return 0; 
    } 

Answer 2

如果你的意思是一个STL std::list，那么这里就是从http://www.cplusplus.com/reference/stl/list/begin/一个简单的例子。

// list::begin 
#include <iostream> 
#include <list> 

int main() 
{ 
    int myints[] = {75,23,65,42,13}; 
    std::list<int> mylist (myints,myints+5); 

    std::cout << "mylist contains:"; 
    for (std::list<int>::iterator it=mylist.begin(); it != mylist.end(); ++it) 
    std::cout << ' ' << *it; 

    std::cout << '\n'; 

    return 0; 
} 

Answer 3

要体现在C++中新增和@karthik，用auto符延长有些过时的解决方案starting from C++11 it can be done shorter：

#include <iostream> 
#include <list> 
using namespace std; 

typedef list<int> IntegerList; 

int main() 
{ 
    IntegerList intList; 
    for (int i=1; i<=10; ++i) 
    intList.push_back(i * 2); 
    for (auto ci = intList.begin(); ci != intList.end(); ++ci) 
    cout << *ci << " "; 
} 

或even easier使用range-based for loops：

#include <iostream> 
#include <list> 
using namespace std; 

typedef list<int> IntegerList; 

int main() 
{ 
    IntegerList intList; 
    for (int i=1; i<=10; ++i) 
     intList.push_back(i * 2); 
    for (int i : intList) 
     cout << i << " "; 
}