opencv的蟒蛇背景减法和运动跟踪

Question

我在谷歌阅读OpenCV中，发现下面的示例代码在网上玩：

import cv2 

def diffImg(t0, t1, t2): 
    d1 = cv2.absdiff(t2, t1) 
    d2 = cv2.absdiff(t1, t0) 
    return cv2.bitwise_and(d1, d2) 

cam = cv2.VideoCapture('vid1.mp4') 

winName = "Movement Indicator" 
cv2.namedWindow(winName, cv2.CV_WINDOW_AUTOSIZE) 

# Read three images first: 
t_minus = cv2.cvtColor(cam.read()[1], cv2.COLOR_RGB2GRAY) 
t = cv2.cvtColor(cam.read()[1], cv2.COLOR_RGB2GRAY) 
t_plus = cv2.cvtColor(cam.read()[1], cv2.COLOR_RGB2GRAY) 

while True: 
    cv2.imshow(winName, diffImg(t_minus, t, t_plus)) 

    # Read next image 
    t_minus = t 
    t = t_plus 
    t_plus = cv2.cvtColor(cam.read()[1], cv2.COLOR_RGB2GRAY) 

    key = cv2.waitKey(10) 
    if key == 27: 
    cv2.destroyWindow(winName) 
    break 

print "Goodbye" 

它产生以下种类的样品视频输出的，我给它：

所以我用这个脚本得到这样的结果。现在我试图弄清楚的是 - 1）获取视频文件中移动对象的边界矩形 2）将该边界矩形的内容从原始视频帧复制到另一个视频帧并将完成的视频写入文件

此外，在试图Kanishak Katahra的解决方案下面，我在下面的截图让在结果窗口中下面的输出在右侧的截图 -

Answer 1

制作的兴趣点在输出你获得1秒。使其余为0. 将其转换为与原始图像大小相同的3D数组。 将原始图像与您获得的输出相乘。

import cv2 
import numpy as np 
from numpy import newaxis 
import time 

def diffimg (a,b,c): 
    t0 = cv2.absdiff(a,b) 
    t1 = cv2.absdiff(b,c) 
    t3 = cv2.bitwise_and(t0,t1) 
    return t3 

cap = cv2.VideoCapture(0) 
t = cap.read() [1] 
tp = cap.read() [1] 
tpp = cap.read() [1] 

t = cv2.cvtColor(t,cv2.COLOR_BGR2GRAY) 
tp = cv2.cvtColor(tp,cv2.COLOR_BGR2GRAY) 
tpp = cv2.cvtColor(tpp,cv2.COLOR_BGR2GRAY) 


while True: 

    img = diffimg(t,tp,tpp) 
    cv2.imshow("motion detct",img) 

    key = cv2.waitKey(10) 


    res,img2 = cap.read() 
    #print img2.shape 

    t = tp 
    tp = tpp 
    tpp = cv2.cvtColor(img2,cv2.COLOR_BGR2GRAY) 

    cv2.imshow('image',img) 
    print img 
    img[img <= 10] = 0 #Try adjusting this value for better results. 
    img[img != 0] = 1 
    img = np.repeat(img[:, :, np.newaxis], 3, axis=2) 
    img3 = np.multiply(img,img2) 
    cv2.imshow('result',img3) 



    if key == 27: 
     cv2.destroyAllWindows() 
     break; 



print "Goodbye User"