我对PHP和SQL比较新,我为自己的页面创建了一个简单的博客工具,并且我一直在关注如何创建注释部分。 我有2个表 一般情况下,它包含了博客文章和其他信息 意见,其中包含注释使用PHP从2个表中选择数据
$servername = "localhost";
$username = "root";
$password = "password";
$dbname = "blog";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error){
die ("connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM general WHERE hidden = 'false' ORDER BY id DESC";
$result = $conn->query($sql);
if ($result->num_rows > 0){
while ($row = $result->fetch_assoc()){
echo "<div class='blogpost'>
<div class='blogbody'></div>";
//I need to do a query into the comments table at this point to find
//all comments matching the criteria to be matched with the post here.
echo "<div class='comments'></div></div>";
}
}
else{
echo "no posts";
}
我设法得到了相关博客文章的工作,但只要我尝试第二次查询中加入
$conn2 = new mysqli($servername, $username, $password, $dbname);
if ($conn2->connect_error){
die ("connection failed: " . $conn2->connect_error);
}
$sql2 = "SELECT * FROM comments WHERE $row["parent"] ORDER BY id DESC";
$result2 = $conn2->query($sql2);
if ($result2->num_rows > 0){
while ($row2 = $result2->fetch_assoc()){
}
}
else{
echo "no comments";
}
这一切都只是打破。我无法投入循环,在开始加载其他帖子之前获取特定帖子的所有评论。
我该如何继续解决这个问题?我可能需要的任何代码示例中的注释一点spoonfeeding,
这就是它打破:'其中$行[ “父母”] ORDER'。将其更改为'WHERE parent = {$ row ['parent']} ORDER'。我现在假设列名称为“parent” - 将其更改为实际的名称。 [它是引用语法错误的引号] – Jeff
,但是为了简化阅读'加入' – Jeff
和__allways__检查错误。在PHP和数据库(mysqli_error) – Jeff