2017-06-02 65 views
0

这就是我的SQL查询作出查询一样多variables.please帮我做一个查询短

$stmt = $con->prepare("select * from fistevent WHERE row_name LIKE 'A%' And Event_Id =? OR row_name LIKE 'B%' And Event_Id =? OR row_name LIKE 'C%' And Event_Id =? OR row_name LIKE 'D%' And Event_Id =? OR row_name LIKE 'E%' And Event_Id =? order by row_name ASC"); 
$stmt->bind_param("s", $_POST['EventId']); 
     $stmt->execute(); 
     $result = $stmt->get_result(); 

如何从价值与阵列数据库比较来自HTML在我的代码

$TicketType =$_POST['Tickettype']; 
$seatS=$_POST['finalSeats']; 
$EventId=$_POST["Eventid"]; 
$sqlData = array(); 

从数据库中获取结果

$stmt = $con->prepare("SELECT * FROM fist WHERE `Id`=? AND `Type`=?") or die($con->error); 

结合的结果

$stmt->bind_param("ss",$EventId , $TicketType); 
$stmt->execute(); 
$stmt->store_result(); 
$stmt-> bind_result($id,$Event_Id,$TicketType,$seats); 
if($stmt->fetch()) 
{ 
$data[] = array($id,$Event_Id,$TicketType,$seats); 
$Tickettype=$TicketType; 
$Rowname=$row_name; 
$Seats=$seats; 
$cats = array_filter(array_map('trim', explode(',', $seatS))); 
foreach($cats as $key => $cat) { 

在这里,我想比较$猫与数据库值$席位,但

while($Seats==$cat) 
{ 
echo "already hold"; 
} 
else 
{ 
echo "hold the seats"; 
} 
} 
} 
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您可以传递您想要搜索的字符或字符串,以便您只能使用一个LIKE函数 –

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您可以请编辑我的代码先生 – krish

回答

1

好像你有相同的事项标识,所以你可以使用查询如

select * from fistevent WHERE (row_name LIKE 'A%' OR row_name LIKE 'B%' OR row_name LIKE 'C%' OR row_name LIKE 'D%' OR row_name LIKE 'E%') And Event_Id =? order by row_name ASC 
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先生的工作。你可以告诉一件事。我怎么能在每一行的前面使用Alfabets ..像A到E – krish

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我不认为有可能在查询中使用这样的范围 – rypskar

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先生你能告诉我请我如何比较我的代码中的值 – krish