这就是我的SQL查询作出查询一样多variables.please帮我做一个查询短
$stmt = $con->prepare("select * from fistevent WHERE row_name LIKE 'A%' And Event_Id =? OR row_name LIKE 'B%' And Event_Id =? OR row_name LIKE 'C%' And Event_Id =? OR row_name LIKE 'D%' And Event_Id =? OR row_name LIKE 'E%' And Event_Id =? order by row_name ASC");
$stmt->bind_param("s", $_POST['EventId']);
$stmt->execute();
$result = $stmt->get_result();
如何从价值与阵列数据库比较来自HTML在我的代码
$TicketType =$_POST['Tickettype'];
$seatS=$_POST['finalSeats'];
$EventId=$_POST["Eventid"];
$sqlData = array();
从数据库中获取结果
$stmt = $con->prepare("SELECT * FROM fist WHERE `Id`=? AND `Type`=?") or die($con->error);
结合的结果
$stmt->bind_param("ss",$EventId , $TicketType);
$stmt->execute();
$stmt->store_result();
$stmt-> bind_result($id,$Event_Id,$TicketType,$seats);
if($stmt->fetch())
{
$data[] = array($id,$Event_Id,$TicketType,$seats);
$Tickettype=$TicketType;
$Rowname=$row_name;
$Seats=$seats;
$cats = array_filter(array_map('trim', explode(',', $seatS)));
foreach($cats as $key => $cat) {
在这里,我想比较$猫与数据库值$席位,但
while($Seats==$cat)
{
echo "already hold";
}
else
{
echo "hold the seats";
}
}
}
您可以传递您想要搜索的字符或字符串,以便您只能使用一个LIKE函数 –
您可以请编辑我的代码先生 – krish