无法在Redshift上使用JOG与generate_series

Redshift上的generate_series函数在按照预期工作时用于简单的select语句。无法在Redshift上使用JOG与generate_series

WITH series AS (
    SELECT n as id from generate_series (-10, 0, 1) n 
) SELECT * FROM series; 
-- Works fine

只要我添加JOIN条件，红移抛出

com.amazon.support.exceptions.ErrorException：功能 generate_series（整数，整数，整数） “不支持”

DROP TABLE testing; 
CREATE TABLE testing (
    id INT 
); 
WITH series AS (
    SELECT n as id from generate_series (-10, 0, 1) n 
) SELECT * FROM series S JOIN testing T ON S.id = T.id; 
-- Function "generate_series(integer,integer,integer)" not supported.

红移版本

SELECT version(); 
-- PostgreSQL 8.0.2 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.4.2 20041017 (Red Hat 3.4.2-6.fc3), Redshift 1.0.1485

有没有任何解决方法可以使这项工作？

来源

2017-10-16 Rahul

你是对的，这在Redshift上不起作用。请参阅here。

最简单的解决方法是事先用该表中的值“手动”创建一个永久表，例如，你可以使用该表为-1000行+1000，然后从该表中选择范围，

因此，对于你的榜样，你会碰到这样的

WITH series AS (
    SELECT n as id from (select num as n from newtable where num between -10 and 0) n 
) SELECT * FROM series S JOIN testing T ON S.id = T.id;

为你做这项工作？

或者，如果您不能创建表事先或不喜欢，你可以使用类似这样

with ten_numbers as (select 1 as num union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9 union select 0) 
,generted_numbers AS 
(
    SELECT (1000*t1.num) + (100*t2.num) + (10*t3.num) + t4.num-5000 as gen_num 
    FROM ten_numbers AS t1 
     JOIN ten_numbers AS t2 ON 1 = 1 
     JOIN ten_numbers AS t3 ON 1 = 1 
     JOIN ten_numbers AS t4 ON 1 = 1 
) 
select gen_num from generted_numbers 
where gen_num between -10 and 0 
order by 1;

来源

2017-10-16 23:00:20

generate_series不红移支持。它只能在领导者节点上独立工作。

一种解决方法是使用row_number针对具有足够数量的行中的任何表：

with 
series as (
    select (row_number() over())-11 from some_table limit 10 
) ...

也，这个问题被问多次已经

来源

2017-10-16 23:28:10 AlexYes

无法在Redshift上使用JOG与generate_series

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