的Oracle 10g：SQL合并行成单排

我有一个查询，返回下面的数据结构：的Oracle 10g：SQL合并行成单排

Course Math Science Computer Chemistry 
------ ---- ------- -------- --------- 
CI101  98 
CI101  87 
CI101    78 
CI101    102 
CI101      23 
CI101      56 
CI101      89 
CI101         45

怎么能有它使用SQL的结构如下：

Course Math Science Computer Chemistry 
------ ---- ------- -------- --------- 
CI101  98  78  23   45 
CI101  87  102  56 
CI101      89

这里SQL我想：

select course, 
    case 
    when subject = 'MATH' then 
     count 
    end as MATH, 
    case 
    when subject = 'SCIENCE' then 
     count 
    end as SCIENCE, 
    case 
    when subject = 'COMPUTER' then 
     count 
    end as COMPUTER, 
    case 
    when subject = 'CHEMISTRY' then 
     count 
    end as CHEMISTRY 
from t_course 
GROUP BY course, subject, count

表结构：

Course Subject  Count 
------ -------  ----- 
CI101  Math   98 
....

提前致谢。

来源

2012-08-01 Ianthe

什么是表结构？ – Chip 2012-08-01 05:22:26

我在问题中添加了表结构 – Ianthe 2012-08-01 05:28:00

在您想要的结果集中，哪一行与另一行有区别？换句话说，为什么没有一个总数为185，科学= 180，计算机= 168，化学= 45的CI101单行？ – Tebbe 2012-08-01 13:16:38

试试这个：

由于我没有甲骨文和我没有看到这个问题的任何答案，我在SQL Server中做到了这一点。这可以很容易地转换成Oracle sql。

我认为，只有一部分需要转换为ROW_NUMBER（）以上（以通过第[count]）作为ROW_NUM这基本上以得到序列号对每个集

select CO.course,MA.count as 'MATH',SC.count as 'SCIENCE',CO.count as 'COMPUTER',CH.count as 'CHEMISTRY' from 
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'MATH')MA full outer join 
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'SCIENCE')SC on SC.row_num=MA.row_num full outer join 
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'COMPUTER')CO on CO.row_num=SC.row_num full outer join 
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'CHEMISTRY')CH on CO.row_num=CH.row_num

请参阅SQL小提琴演示here

来源

2012-08-01 06:35:51

的Oracle 10g：SQL合并行成单排

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